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Elza [17]
2 years ago
9

julianna wrote -16+ x = -8 on the board.Do not solve.Tell how you would simplify julianna's expression?

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
6 0

Answer:

x = 8

Step-by-step explanation:

→ Add 16 to both sides

x = 8

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Alexis sold 3/8 of her raffle tickets on the first day. She sold 88 raffle tickets during the first week and the remaining 32 ra
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She would have sold 45 tickets on the first day

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3 years ago
Dinesh has 28 points in a trivia game. He answers a question correctly and earns 35 points. Then, he answers a multipart questio
ioda

Answer:

The answer for the problem would be -12

Step-by-step explanation:

(28+35) = 63

63-75= -12

6 0
3 years ago
A camera shop purchases a camera for $56.98 and sells it for $102.56. What is the percent of markup?
Amiraneli [1.4K]

Answer:

180%

Step-by-step explanation:

Set up an equation:

Variable x = percent of markup

102.56/56.98 = x/100

Cross multiply

102.56 × 100 = 56.98 × x

10,256 = 56.98x

Divide both sides by 56.98:

179.99297.... = x

Round to nearest whole number:

180 = x

Check your work:

56.98 × 180%

Convert the percentage into a decimal:

56.98 × 1.80

102.564

Round to nearest cent:

102.56

Correct!

8 0
3 years ago
Find the value of x.
svetoff [14.1K]

Answer:

68

Step-by-step explanation:

1) Find the interior angle using relations of angles in straight line I.e ( sum of angles in a straight line is 180 ) and we know the sum of all the interior angle of quadrilateral is 360 degree .

2) Solve further for x.

5 0
3 years ago
Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
3 years ago
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