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Advocard [28]
2 years ago
6

Which of these frequency counts would be represented by the smallest

Mathematics
1 answer:
vazorg [7]2 years ago
8 0

The frequency count that would be represented by the smallest number of dots on a dot plot is 5 (option A).

<h3>What is a dot plot?</h3>

A dot plot is a graph that has similarities with a histogram that is used to represent the frequency of a data set. The dots in the dot plot represent the frequency of the data. The greater the frequency of a data, the greater the number of dots.

Given the information in this question, 8 would have the highest number of dots while 5 would have the smallest number of dots. A dot plot is an efficient way of representing frequencies. It is also suitable for small data sets.

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dolphi86 [110]

Answer:

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Step-by-step explanation:

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4 years ago
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Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
Aloiza [94]

Answer:

0.70275

Step-by-step explanation:

Data provided in the question:

4e²ˣ⁻¹ -1 = 5

now solving for 'x'

⇒ 4e²ˣ⁻¹ = 5 + 1

or

⇒ 4e²ˣ⁻¹ = 6

or

⇒ e^{(2x-1)} =\frac{6}{4}

or

⇒ e^{(2x-1)} =\frac{3}{2}

now,

taking natural log both sides, we get

⇒ 2x - 1 = \ln(\frac{3}{2})

also,

we know

⇒ \log(\frac{A}{B}) = \log(A)+\log(B)

thus,

⇒ 2x - 1 = ln(3) - ln(2)

or

⇒ 2x - 1 = 1.0986 - 0.6931

or

⇒ 2x - 1 = 0.4055

or

⇒ 2x = 0.4055 + 1

or

⇒ 2x = 1.4055

or

⇒ x = 0.70275

3 0
3 years ago
Help me please im in a rush i need help
GREYUIT [131]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

Area of shaded region = 34 cm²

\textsf{  \underline{\underline{Steps to solve the problem} }:}

Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.

Area (big) :

\qquad❖ \:  \sf \:13 \times 6

\qquad❖ \:  \sf \:78 \:  \:c m {}^{2}

Area (small) :

\qquad❖ \:  \sf \:11 \times 4

\qquad❖ \:  \sf \:44 \:  \: cm {}^{2}

Area of shaded region :

\qquad❖ \:  \sf \:78 - 44

\qquad❖ \:  \sf \:34 \:  \: cm {}^{2}

\qquad \large \sf {Conclusion}  :

Area of shaded region = 34 cm²

8 0
2 years ago
Can someone help me with the question please
alexandr1967 [171]

Answer:

Purple line: 4

Red dashed line: 2

Blue line: 1/2

Step-by-step explanation:

The purple line is the steepest line, therefore it has the biggest constant of proportionality or slope. Since 4 is the biggest number among the others, we attribute it to the purple line (the one with the point C on it).

Think of it this way:

y = ax+b \\

here b = 0 so y = ax

The greater a is, the greater y is. So for any value of x, y will be become bigger and bigger if we increase the value of a.

Take for example this one:

y = 2x \\

Take x=2\\ therefore y =4

Now take y = 4x and take x =2 therefore y = 8

When we increased this constant of proportionality, as you can see from 2 to 4, the value of y increase from 4 to 8.

Hope this is helpful. Think of it really carefully, and I'm sure you'll grasp the concept.

7 0
3 years ago
Answer if u love cats &amp; dogs
eimsori [14]

Answer:

<em>(7, 5.25)</em> lies on the graph.

Step-by-step explanation:

We are given the following values

x = 4,   6,  8, 12 and corresponding y values are:

y = 3, 4.5, 6, 9

Let us consider two points (4, 6) and (6, 4.5) and try to find out the equation of line.

Equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given as:

y=mx+c

where m is the slope.

(x,y) are the coordinates from where the line passes.

c is the y intercept.

Here,

x_{1} = 4\\x_{2} = 6\\y_{1} = 3\\y_{2} = 4.5

Formula for slope is:

m = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \dfrac{4.5-3}{6-4}\\\Rightarrow m = \dfrac{1.5}{2}\\\Rightarrow m = \dfrac{3}{4}

Now, the equation of line becomes:

y=\dfrac{3}{4}x+c

Putting the point (4,3) in the above equation to find <em>c</em>:

3=\dfrac{3}{4}\times 4+c\\\Rightarrow 3=3+c\\\Rightarrow c =0

So, final equation of given function is:

y=\dfrac{3}{4}x

OR

4y=3x

As per the given options, the point <em>(7, 5.25) </em>satisfies the equation.

So correct answer is (7, 5.25).

6 0
3 years ago
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