Question

A spaceship with a constant speed of 0. 800c relative to earth travels to a star that is 4. 30 light-years from earth. how much time for this trip would elapse on a clock on board the spaceship?

Answer 1

Main Answer:

Given  speed of spaceship v = 0.8c = 0.8 * 3 x 10^8 m/s

Speed of spaceship v = 2.4 x 10^8 m/s

Distance need to be travelled d = 4.3 light years

we know that 1 light year  = 9.461 x 10^15 m

Distance need to be travelled d = 4.3 x 9.461 x 10^15

d = 40.6823 x 10^15 m

Time taken for the trip would elapse on a clock on board the spaceship

t = distance/ velocity

t = 40.6823 x 10^15 / 2.4 x 10^8

t = 16.95 x 10^7 sec

t = 4.71 x 10^4 hours

Explanation:

What is light year?

Light year is defined as the distance travelled by the light in one year. In a year, light travels through 300000 km per sec in the interstellar space.

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