What would be the weight of a 59.1-kg astronaut on a planet with the same density as Earth and having twice Earth's radius?

1 answer:

5 0

You could always directly use F = G M m / r², but that takes forever.

It is best to know that, on Earth's surface, the astronaut would weigh 
F = m g = 579.2 N 
where m = 59.1 kg and g = 9.8 m/s². 

You then notice from F = G M m / r² that doubling the mass of the earth would double his weight and doubling the radius would give 1/4 his original weight. So... 
F = 1/4 * 2 * 579.2 N = 290 N

You might be interested in

If the radius of a coin is 1 cm then calculate its area.

igor_vitrenko [27]

Answer:

3.14*1²

3.14 cm²

I hope this will help

5 0

3 years ago

Read 2 more answers

THE LARGEST HORIZONTAL PLATES IS SEPARATED BY 4mm .The plate is at the potencial of -6V . What potencial should be applied to th

Serhud [2]

Answer:

V₂ = -22 V

Explanation:

Electric potential and field are related

ΔV = - E d

where ΔV is the potential difference between the plates, E the electric field and d the separation between the plates

In this exercise we are given the parcionero d = 4 mm = 0.004 m, the potential of one of the plates V1 = -6V and the value of the electric field E = 4000 V / m

V₂- V₁ = - E d

V₂ = - Ed + V₁

V₂ = - 4000 0.004 + (- 6)

V₂ = -16 - 6

V₂ = -22 V

6 0

3 years ago

Calculate the momentum of a 1,500 kg car traveling at 6 m/s.

mamaluj [8]

Answer: 9000 kgm/s

Explanation:

Mass of car = 1500 kg