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Sophie [7]
3 years ago
14

What would be the weight of a 59.1-kg astronaut on a planet with the same density as Earth and having twice Earth's radius?

Physics
1 answer:
Olegator [25]3 years ago
5 0
You could always directly use F = G M m / r², but that takes forever. 

<span>It is best to know that, on Earth's surface, the astronaut would weigh </span>
<span>F = m g = 579.2 N </span>
<span>where m = 59.1 kg and g = 9.8 m/s². </span>

<span>You then notice from F = G M m / r² that doubling the mass of the earth would double his weight and doubling the radius would give 1/4 his original weight. So... </span>
<span>F = 1/4 * 2 * 579.2 N = 290 N </span>
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Which particle of the atom has a negative charge?
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D, electron, the nucleus is not a single particle to begin with, the proton has a positive charge, a neutron has a neutral charge or no charge, and an electron has a negative charge
3 0
3 years ago
The stars in the sky are organized into groups of stars called constellations which appear near each other in the sky but are no
bezimeni [28]

Answer:

The International Astronomical Union (IAU)  has accepted 88 constellations in the sky.

Explanation:

Constellations has been used since the beginnings of civilizations and each one of them named them as they considered appropiate. It means Greeks' constellations were different than the ones described by Chinese, so it was necessary to gather all these constellations and make a great record with all of them, but there was a problem: Some constellations from different civilizations overlaped because they shared the same stars. There was necessary to put some order on this and that is when in 1922 the International Astronomical Union (IAU) defned a set of 88 moderm constellations  that would become the international standard to look at the night sky. Each one of them is unique and does not share stars with the other constellations.  

6 0
2 years ago
An engineer is designing a runway for a witch. Several brooms will use the runway and the engineer must design it so that it is
jonny [76]

Answer:

1170 m

Explanation:

Given:

a = 3.30 m/s²

v₀ = 0 m/s

v = 88.0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(88.0 m/s)² = (0 m/s)² + 2 (3.30 m/s²) (x - 0 m)

x = 1173.33 m

Rounded to 3 sig-figs, the runway must be at least 1170 meters long.

6 0
3 years ago
What is the period of a soundwave whose wavelength is 20.0 m? Use values from the book and show ALL of your work.
Liono4ka [1.6K]
<h3><u>Answer;</u></h3>

Period = 1/17 seconds

<h3><u>Explanation;</u></h3>
  • Wavelength is related to period by the expression:

<em>speed = wavelength / period </em>

  • If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.

<em>Given the speed of sound wave as 340 m/s </em>

<em>Period = Wavelength/ speed</em>

<em>            = 20 m/340 m/s</em>

<em>            </em><u><em>= 1/17 seconds</em></u>

7 0
2 years ago
How does the phrase studying grammar function in sentence 4? A) main verb B) direct object C) subject complement D) subject of t
lisabon 2012 [21]

Answer: (b) direct object

Explanation:

6 0
3 years ago
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