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Oliga [24]
2 years ago
15

An object moving on a horizontal, frictionless surface makes a glancing collision with another object initially at rest on the s

urface. In this case, which of the following is true about momentum and kinetic energy?
a. Momentum is always conserved, and kinetic energy may be conserved.
b. Kinetic energy is always conserved, and momentum may be conserved.
c. Momentum is always conserved, and kinetic energy is never conserved.
d. Both momentum and kinetic energy are always conserved.
e. Neither momentum nor kinetic energy is conserved.
Physics
1 answer:
cluponka [151]2 years ago
6 0

Answer:

Momentum is always conserved, and kinetic energy may be conserved.

Explanation:

For an object moving on a horizontal, frictionless surface which makes a glancing collision with another object initially at rest on the surface, the type of collision experienced by this objects can either be elastic or an inelastic collision depending on whether the object sticks together after collision or separates and move with a common velocity after collision.

If the body separates and move with a common velocity after collision, the collision is elastic but if they sticks together after collision, the collision is inelastic.

Either ways the momentum of the bodies are always conserved since they will always move with a common velocity after collision but their kinetic energy may or may not be conserved after collision, it all depends whether they separates or stick together after collision and since we are not told in question whether or not they separate, we can conclude that their kinetic energy "may" be conserved.

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Vitek1552 [10]

(a) y(t)=250 - 4.9 t^2

For an object in free-fall, the vertical position at time t is given by:

y(t) = h + ut - \frac{1}{2}gt^2

where

h is the initial vertical position

u is the initial vertical velocity

g = 9.8 m/s^2 is the acceleration of gravity

t is the time

In this problem,

h = 250 m

u = 0 (the stone starts from rest)

So, the vertical position of the stone is given by

y(t) = 250 - \frac{1}{2}(9.8) t^2 = 250 - 4.9 t^2

(b) 7.14 s

The time it takes for the stone to reach the ground is the time t at which the vertical position of the stone becomes zero:

y(t) = 0

Which means

y(t) = h - \frac{1}{2}gt^2=0

So for the stone in the problem, we have

250 - 4.9 t^2 = 0

Solving for t, we find:

t=\sqrt{\frac{250}{4.9}}=7.14 s

(c) -70.0 m/s (downward)

The velocity of an object in free fall is given by the equation

v(t) = u - gt

where

u is the initial velocity

g = 9.8 m/s^2 is the acceleration of gravity

t is the time

Here we have

u = 0

So if we substitute t = 7.14 s, we find the velocity of the stone at the time it reaches the ground:

v=0-(9.8 m/s^2)(7.14 s)=-70.0 m/s

The negative sign means the direction of the velocity is downward.

(d) 6.94 s

In this situation, the stone is thrown downward with an initial speed of 2 m/s, so its initial velocity is

u = -2 m/s

So the equation of the vertical position of the stone in this case is

y(t) = h + ut - \frac{1}{2}gt^2=250 - 2t - 4.9 t^2

By solving the equation, we find the time t at which the stone reaches the ground.

We find two solutions:

t = -7.35 s

t = 6.94 s

The first solution is negative, so it has no physical meaning, therefore we discard it. So, the time it takes for the stone to reach the ground is:

t = 6.94 s

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patriot [66]

Answer:

Explained below

Explanation:

For the geometric meaning, I've attached a parallelogram showing two vectors a and B and also the angle between them as θ.

We can see that the two vectors are adjacent to each other.

So the magnitude of the product of the two vectors is simply the area of the parallelogram which is base x height. Thus;

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This can be rewritten as;

|a|•|b| sin θ

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<span>"For every action, there is an equal and opposite reaction."
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Option C. The measurement with the most significant number is 6.600 cm.

<h3>What is significant number?</h3>

Significant numbers are numbers that have significance or meaning and give more precise details about the value of the entire numbers.

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  • 0.00066 cm -------> 2 significant numbers
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Thus, the measurement with the most significant number is 6.600 cm.

Learn more about significant numbers here: brainly.com/question/24491627

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