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LekaFEV [45]
2 years ago
12

What is the molar solubility of CAF2in pure water at 25°c?

Chemistry
1 answer:
natali 33 [55]2 years ago
6 0

Answer:

1.7x10g per 100cc

Explanation:

The solubility product of Caf, at 25 °C is about X x 10-11 mol/L.

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4 years ago
Describe two tests that you can run to determine if something is a substance or a mixture.
ryzh [129]

The difference between a substance and a mixture is that a substance is one of a kind, a material of the same composition throughout, on the contrary, a mixture is one or more different substances brought together and mixed together without changing the nature of each single substance.

One way to test it is to take two substances like sand and table salt. They should each be in granular form and in adequate amount to mix. Neither substance has changed after mixing the two. Even though it may not be easy or convenient to accomplish, each substance could be separated out from the mixture.

When it comes to two substances in lump form, it would not be a mixture when one lump is positioned next to the other lump because there are not enough pieces to combine.

However, there could be a mixture of three substances, like sand, table salt and graphite powder and there could be a mixture with four substances, etc., ad infinitum.

Mixtures are of solid substances in general. On the other hand, one starts referring to solutions when liquids are involved. Gases can be a mixture like for example, air is a mixture with nitrogen, oxygen, argon, etc.


4 0
3 years ago
An idea based on observations with no experimental evidence is a:
maxonik [38]
A Hypothesis.

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7 0
3 years ago
What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M
professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

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3 years ago
How many moles of CsXeF7 can be produced from the reaction of 12.5 LOL of celsium Fluoride with 10.0 mol of xenon hexafloride
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What the what I do not get it
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3 years ago
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