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3 years ago

Which tool is most suitable for a chemist to measure the mass of a liquid

Chemistry

2 answers:

I am Lyosha [343]3 years ago

7 0

Chemists use beakers, flasks, burets and pipets to measure the volume of liquids. Plz mark as brainliest

telo118 [61]3 years ago

7 0

Answer:

The most suitable tool is using a graduated cylinder and a calibrated balance.

Explanation:

To measure the mass of a liquid, first you have to define an specific volume of liquid to measure (example 200 milliliters), then using a graduated cylinder you measure this quantity and put it all on the balance. You read the mass value (example 285 grams). To finish you have to measure the mass of the graduated cylinder empty (example 100 grams) and then subtract it to the weight of the liquid with the calibrated cylinder (example 285 g - 100 g = 185 g).

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A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq

zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4 = 90.03 g/mol

Step 2: Calculate initial moles of H2C2O4

Moles H2C2O4 = mass / molar mass

Moles H2C2O4 = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0

3 years ago

The half reaction of an oxidation-reduction shows that iron gains electrons. What does this electron gain mean or iron?

ale4655 [162]

Answer:

C. its reduced

Explanation:

4 0

3 years ago

How many moles are in 2.5L of 1.75 M Na2CO3

mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M $Na_2CO_3$

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of solution = 1.75 M

Volume of solution = 2.5 L

Putting values in equation , we get:

$1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol$

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3 years ago

Hanna hypothesizes that granite is denser than sandstone. How can Hanna test her hypothesis?

kherson [118]

To test if the hypothesis is correct, a good way is to think of it this way:
Density = mass/volume, right?
Calculate the mass and volume of each and do the equation; this will test your hypothesis.
You will be left with the density of each. But, make sure that the sample sizes are the same (controlled variable) otherwise it will be an unfair test.

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3 years ago

The average strength of a hydrogen bond is approximately what percent of the average strength of a covalent bond?

lozanna [386]

<span>Hydrogen bonds are approximately 5% of the bond strength of covalent bonds, for example (C-C or C-H bonds).
Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0,057 = 5,7 %.</span>

8 0

3 years ago