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Luba_88 [7]
2 years ago
12

When discharging, what percentage of the starting voltage will the capacitor reach after 5rc?

Physics
1 answer:
Ahat [919]2 years ago
6 0

When discharging equivalent of 0% starting voltage will the capacitor reach after 5RC.

V(t) = V0e-t/RC = V0b initially.

<h3>What is capacitor?</h3>
  • In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component.
  • Capacitance refers to a capacitor's effect.
  • The terminals in a capacitor are connected to two metal plates that are spaced apart by a dielectric, a non-conducting material.
  • Two pieces of aluminum foil, along with a piece of paper, can be used to create a capacitor (and some electrical clips).
  • It won't have a lot of storage capacity, so it won't be a great capacitor, but it will still function.
<h3>What are the different types of capacitors?</h3>

The numerous kinds of capacitors and their applications.

  • Frequently utilized in radio tuning circuits is air.
  • Mylar: The material most frequently used in timer circuits for clocks, alarms, and counting.
  • Good for high-voltage applications is glass.
  • Ceramic is used in X-ray, MRI, and other high-frequency devices.
  • a powerful capacitor fuels hybrid and electric vehicles.

Learn more about capacitors here:

brainly.com/question/17584935

#SPJ4

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A 4 kilogram box is at rest on a frictionless floor. A net force of 12 newtons acts on it. What is the acceleration of the box?
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Answer:

<h2>3 m/s^2</h2>

Explanation:

Step one:

given

Mass m= 4kg

Force F= 12N

Required

Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force

F=ma

a=F/m

a=12/4

a=3 m/s^2

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2. Which of the following accurately describes the effects of temperature changes on solids? A. If the temperature of a solid is
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A student (m = 68 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a
Gnesinka [82]

Answer:

5.7141 m

Explanation:

Here the potential and kinetic energy will balance each other

mgh=\frac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}

This is the initial velocity of the system and the final velocity is 0

t = Time taken = 0.04 seconds

F = Force = 18000 N

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}

From Newton's second law

F=ma\\\Rightarrow F=m\frac{v-u}{t}\\\Rightarrow 18000=68\frac{0-\sqrt{2gh}}{0.04}\\\Rightarrow \frac{18000}{68}\times 0.04=-\sqrt{2\times 9.81\times h}\\\Rightarrow 10.58823=-\sqrt{2\times 9.81\times h}

Squarring both sides

112.11061=2\times 9.81\times h\\\Rightarrow h=\frac{112.11061}{2\times 9.81}\\\Rightarrow h=5.7141\ m

The height from which the student fell is 5.7141 m

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