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Luba_88 [7]
2 years ago
12

When discharging, what percentage of the starting voltage will the capacitor reach after 5rc?

Physics
1 answer:
Ahat [919]2 years ago
6 0

When discharging equivalent of 0% starting voltage will the capacitor reach after 5RC.

V(t) = V0e-t/RC = V0b initially.

<h3>What is capacitor?</h3>
  • In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component.
  • Capacitance refers to a capacitor's effect.
  • The terminals in a capacitor are connected to two metal plates that are spaced apart by a dielectric, a non-conducting material.
  • Two pieces of aluminum foil, along with a piece of paper, can be used to create a capacitor (and some electrical clips).
  • It won't have a lot of storage capacity, so it won't be a great capacitor, but it will still function.
<h3>What are the different types of capacitors?</h3>

The numerous kinds of capacitors and their applications.

  • Frequently utilized in radio tuning circuits is air.
  • Mylar: The material most frequently used in timer circuits for clocks, alarms, and counting.
  • Good for high-voltage applications is glass.
  • Ceramic is used in X-ray, MRI, and other high-frequency devices.
  • a powerful capacitor fuels hybrid and electric vehicles.

Learn more about capacitors here:

brainly.com/question/17584935

#SPJ4

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Which of the following is not a sedimentary structure?A) Magma emplacementB) Mud cracksC) Ripple marksD) Cross beds
lawyer [7]

Answer:

A) Magma emplacement

Explanation:

Sedimentary structures forms during deposition of sediments. It can also form after sediments have been deposited. Sedimentary structures can only be found in sedimentary rocks. Some examples include mud cracks, ripple marks, cross stratification, potholes, etc

Magma emplacement is an igneous process which describes the different mechanisms by which magma can be emplaced. It is only typical of igneous rocks.

6 0
3 years ago
List three reasons why knowing how to graph movement can help you on a practical level.
valina [46]

<span>-1.0 m/s2
1.0 m/s2
-5.0 m/s2
5.0 m/s2
0.24 m/s<span>2</span></span>
6 0
3 years ago
A 1400.0 kg car crests a 3200.0 m pass in the mountains and briefly comes to rest. The car descends 1000 m before climbing and c
rjkz [21]

Answer:

a) v = 88.54 m/s

b) vf = 26.4 m/s

Explanation:

Given that;

m = 1400.0 kg

a)

by using the energy conservation

loss in potential energy is equal to gain in kinetic energy

mg × ( 3200-2800) = 1/2 ×m×v²

so

1400 × 9.8 × 400 = 0.5 × 1400 × v²

5488000 = 700v²

v² = 5488000 / 700

v² = 7840

v = √7840

v = 88.54 m/s

b)

Work done by all forces is equal to change in KE

W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)

we substitute

1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf²  -0 )

488000 = 700 vf²

vf² = 488000 / 700

vf² = 697.1428

vf = √697.1428

vf = 26.4 m/s

4 0
4 years ago
Which of the following is an important step in the process of conflict resolution?
4vir4ik [10]
A would be the correct answer. Its the only one to make sense since you are trying to solve the conflict!
7 0
4 years ago
Read 2 more answers
A plane takes off in san francisco at noon and flies toward the southeast. an hour later, it is 400 kilometers east and 300 kilo
eduard
This first step involves a right triangle. If the plane is 400 km east and 300 km south of the origin, and it flew in a straight line, then you can construct a right triangle with side lengths 300, 400, and c. You may recognize that these are multiples of the Pythagorean triple 3, 4, 5, so the side length c is 500 km. Otherwise, you would write 
c^2 = 300^2+400^2 \\ c = 500. 

This second step is, if I am correctly interpreting "degrees south of east," to find the angle formed by the horizontal line representing the east and the path of the plane. I made a diagram that does just that (see attached). You can use a trig function of one of the angles to solve. I chose
tan(C)= \frac{3}{4}  \\  arctan( \frac{3}{4})=36.870. Thus, I believe it is 37° south of east.

5 0
3 years ago
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