All categories

3 years ago

If a 75-kg skater starts his skate at 8.0m, at his lowest point (height = 0), what is

Physics

1 answer:

Tanya [424]3 years ago

6 0

Mgh= 1/2 m v^2
gh= 1/2 v^2 9.8 * 8= 1/2 v^2
solve for v
V = sqrt(2gH)where H = 8 m.

You might be interested in

Why are plate tectonics a theory?

liubo4ka [24]

Plate tectonicss a property of the behavior of systems, plates, that are far from fundamental, like particles. So any statement about them is a theory.

8 0

3 years ago

A uniformly charged ring of radius 10.0 cm has a total charge of 71.0 μC. Find the electric field on the axis of the ring at the

oee [108]

Answer:

General Expression: E = kql/(l² + r²)^(3/2)

(a) 6.3 MN/C

(b) 22.8 MN/C

(d) 0.63 MN/C

Explanation:

The general expression for electric field along axis of a uniformly charged ring is:

E = kqL/(L² + r²)^(3/2)

where,

E = Electric Field Strength = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q = Total Charge = 71 μC = 71 x 10⁻⁶ C

L = Distance from center on axis

r = radius of ring = 10 cm = 0.1 m

(a)

L = 1 cm = 0.01 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.01 m)/[(0.01 m)² + (0.1 m)²]^(3/2)

E = (6390 N.m³/C)/(0.00101 m³)

E = 6.3 x 10⁶ N/C = 6.3 MN/C

(b)

L = 5 cm = 0.05 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.05 m)/[(0.05 m)² + (0.1 m)²]^(3/2)

E = (31950 N.m³/C)/(0.00139 m³)

E = 22.8 x 10⁶ N/C = 27.4 MN/C

(c)

L = 30 cm = 0.3 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.3 m)/[(0.3 m)² + (0.1 m)²]^(3/2)

E = (191700 N.m³/C)/(0.03162 m³)

E = 6.1 x 10⁶ N/C = 6.1 MN/C

(d)

L = 100 cm = 1 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(1 m)/[(1 m)² + (0.1 m)²]^(3/2)

E = (639000 N.m³/C)/(1.015 m³)

E = 0.63 x 10⁶ N/C = 0.63 MN/C

8 0

3 years ago

I need heelp plzzzzz can anyone heelp mee

sveticcg [70]

Answer:

e) 1.04

Explanation:

4 0

3 years ago

Read 2 more answers

SOMEBODY PLEEASEEE HELP A STRUGGLING HIGHSCHOOLERRRR +(

CaHeK987 [17]

Explanation:

What is the weight of a 2.00-kilogram object on the surface of Earth?

2.00 N

4.91 N

9.81 N

19.6 N

Given parameters:

Mass of the object = 2kg

Unknown:

Weight of the object = ?

Solution:

The weight of an object is the force of gravity acting on the object;

Weight = mass x acceleration due to gravity

Acceleration due to gravity = 9.8m/s²

Now insert the parameters and solve;

Weight = 2 x 9.8 = 19.6N

A person weighing 785 Newtons on the surface of the Earth would weigh 47 Newtons on the surface of Pluto. What is the magnitude of the gravitational acceleration on the surface of Pluto?

1.7 m/s²

0.59 m/s²

0.29 m/s²

9.8 m/s²

Given parameters:

Weight on Earth = 785N

Weight on Pluto = 47N

Unknown:

Acceleration due to gravity on Pluto = ?

Solution

The mass of the body both on Earth and Pluto is the same.

Weight = mass x acceleration due to gravity

Now find the mass on Earth;

Acceleration due to gravity on Earth = 9.8m/s²

785 = mass x 9.8

mass = $\frac{785}{9.8}$ = 80.1kg

So;

Acceleration due to gravity on Pluto = $\frac{Weight on Pluto}{mass }$

Acceleration due to gravity = $\frac{47}{80.1}$ = 0.59m/s²

5 0

3 years ago

Question is linked below! BRAINLIEST rewarded to the first person to answer!!

n200080 [17]

Answer:

i think its secondary succession

Explanation:

because secondary succession happens when theirs an existing forest then its burnt down and a new ecosystem happens

4 0

3 years ago