1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rodikova [14]
3 years ago
9

If a 75-kg skater starts his skate at 8.0m, at his lowest point (height = 0), what is

Physics
1 answer:
Tanya [424]3 years ago
6 0
Mgh= 1/2 m v^2
gh= 1/2 v^2 9.8 * 8=  1/2 v^2
solve for v
V = sqrt(2gH)where H = 8 m.
You might be interested in
If a calibration curve of absorbance vs procaine hydrochloride concentration (mol L') is linear with the equation y = 240000x fo
coldgirl [10]

Answer:

8000 L/ mol cm is the value of the molar absorptivity coefficient.

Explanation:

The slope of the absorbance- concentration graph is equal to the product of path length and  molar absorptivity coefficient.

\frac{dA}{dc}=\epsilon l

\frac{dA}{dc}= Rate of change of absorbance with respect to concentration

\epsilon = molar absorptivity coefficient

l = Path-length

Given the slope of graph of absorbance vs procaine hydrochloride concentration.

y = 240000 x (linear equation)

Path length of cuvette = 3 cm

A=240000 c

A=\epsilon c\times l=(\epsilon l)\times c

240000=\epsilon \times 3

\epsilon =\frac{24000}{3}=8000

The units of \epsilon = 8000 l/mol cm

8000 L/ mol cm is the value of the molar absorptivity coefficient.

3 0
3 years ago
Write any three applicataion pressure in our daily life ?​
Nina [5.8K]

Answer:

because the gravity of the earth

4 0
2 years ago
An object with charge q = −6.00×10−9 C is placed in a region of uniform electric field and is released from rest at point A. Aft
sergeinik [125]

Answer:

a) 80 V

b) The magnitude of the electric field is 100 N/C and the direction of the electric field is from point B to point A where the electric field is toward the negative charge

Explanation:

<u>Given :</u>

We are given an object with charge q = -6.00 x I0^-9 C starts moving from the rest at point A, which means its kinetic energy at point A is zero ( K_{A}= 0) to the point B at distance l = 0.500m where its kinetic energy is (  K_{B}= 5.00 x 10^-7J) . Also, the electric potential of q at point A is VA = + 30.0 v.

<u>Required :</u>

<em>(a) We are asked to find the electric potential VB </em>

<em>(b) We want to determine the magnitude and the direction of the electric field E. </em>

<u> Solution </u>

(a) We are given the values for VA,K_{B} and q so we want to find a relationship between these three parameters and VB to get the value of VB.

As we have two states, at points A and B , where the charge moved from A to B due to the applied electric field. The mechanical energy of the object is conservative during this travel, and we can apply eq(1) in this situation:

                                   K_{A} +U_{A} =K_{B} +U_{B} .........................................(1)                                          

Where K_{A}= 0 and the potential energy U of the charge is given by U = q V

where V is the electric potential.  So, equation (1) will be in the form :

                                  0+qVA=K_{B} +qVB                      (Divide by q)

                                         VA=K_{B} /q + VB                  (solve for VB)

                                         VB=VA- K_{B}/q .......................................(2)

We get the relation between VB, VA and K_{B}, now we can plug our values for VA, K_{B} and q into equation (2) to get VB

                                         VB=VA- K_{B}/q

                                              =30V-(5.00 x 10^-7J)/(-6.00 x I0^-9)

                                              =80 V

(b) After we calculated VB we can use equation a to get the electric field E that applied to the charge q, where the potential difference between the two points equals the integration of the electric field multiplied by the distance l between the two points

                                   VA-VB =\int\limits^1_0 {E} \, dl...................................(a)

                                               =E\int\limits^1_0 {} \, dl

                                   VA-VB=El                      (solve for E)

                                            E= VA-VB/l..................................(3)

Now let us plug our values for VA, Vs and l into equation (3) to get the electric field E

                                            E= VA-VB/l

                                              =-100 N/C

The magnitude of the electric field is 100 N/C and the direction of the electric field is from point B to point A where the electric field is toward the negative charge

5 0
3 years ago
How do you draw an ear
Neporo4naja [7]

Answer:

drawing of ear step by step

8 0
3 years ago
What is the speed of sound in air at 40°C?
Blababa [14]
343 meters per second Is the answer
4 0
3 years ago
Read 2 more answers
Other questions:
  • I really need help with this, i dont know what to do first, PLEASE I NEED HELP DUE TOMORROW!!!
    6·1 answer
  • In one type of solar energy system, sunlight heats the air within solar panels, which heats copper tubes filled with water. what
    9·1 answer
  • You are designing a flash camera and wish to store 3j of energy in a capacitor to power the flashbulb. the circuitry of the came
    8·1 answer
  • White light is composed of all the colors of the visible light spectrum. The spectrum is usually said to consist of
    15·2 answers
  • A 600 g model rocket is on a cart that is rolling to the right at a speed of 2.5 m/s. The rocket engine, when it is fired, exert
    8·2 answers
  • What does an alpha particle consist of?
    6·2 answers
  • 7. Mac and Tosh are arguing about the track design. Mac claims that the car is moving fastest at point F because it is furthest
    13·1 answer
  • A car initially miving at 0.5m/s along a track.the car come to rest after travelling 1m.the car is repeated on the same of track
    15·1 answer
  • My teacher ask me to slove this question please help me.
    11·1 answer
  • If 340J of work is done to move 1.5 x 10^-3C of charge from a positive plate to a
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!