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3 years ago

Factorise:x^2-y^2-x-y

Mathematics

1 answer:

ivanzaharov [21]3 years ago

7 0

9514 1404 393

Answer:

(x -y -1)(x +y)

Step-by-step explanation:

The expression can be factored by grouping.

x^2 -y^2 -x -y = (x^2 -y^2) -(x +y)

= (x -y)(x +y) -1(x +y)

= (x -y -1)(x +y)

_____

It is useful to know that a difference of squares is factored as ...

a^2 -b^2 = (a -b)(a +b)

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The weight in pounds of a baby in the first six months of life can be modeled by the

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Step-by-step explanation:

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3 years ago

Which point on the axis satisfies the inequality

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3 years ago

Read 2 more answers

A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin

sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

$P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}$

The probability that they each win six games is k=6.

$P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}$

$P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625$

$P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625$

$P(X=6)=0.225$

Therefore, The probability that they each win six games is 0.225.

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3 years ago

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klemol [59]

Answer: (2*5.4*7)+(2*5*8)+(7*8)

Step-by-step explanation:

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2 years ago

Factorise:x^2-y^2-x-y​

Factorise:x^2-y^2-x-y