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nadya68 [22]
2 years ago
6

Driving safely at night requires seeing well not only in low light conditions, but also being able to see low contrast

Physics
1 answer:
Monica [59]2 years ago
8 0

Answer:

True

Explanation:

Driving safely at night requires seeing well not only under low light, but also requires drivers to see low-contrast objects.

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A train travels 4,000,000 m from New York to Los Angeles and takes about 42 hours to make the entire trip. What is its speed in
barxatty [35]

Answer:

195,714,000 meters per second

I hope this helps!

5 0
3 years ago
HEEEEELP!!!!!! :((( help me with this exercise.
kirill [66]

Answer:

  • See the graph attached with the vectors.

Explanation:

The exercise is to draw the corresponding vectors:

     2\vec a\\\\3\vec c\\\\3\vec d\\\\3\vec f\\\\2\vec b

Every one is the multiplication of a scalar by a vector.

The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.

Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.

For instance, the vector 2\vec a is represented with an arrow in the same direction of \vec a and with twice its length.

The figure attached contains the five requested vectors using the procedure explained above.

7 0
3 years ago
A parallel-plate capacitor is made from two aluminum-foil sheets, each 5.9 cm wide and 5.6 m long. Between the sheets is a Teflo
Zarrin [17]

Answer:

1.98 x 10⁻⁷ F

Explanation:

w = width of the sheet = 5.9 cm = 0.059 m

L = length of the sheet = 5.6 m

Area of the sheet is given as

A = L w = (5.6) (0.059) = 0.3304 m²

d = distance between the sheets = 3.1 x 10⁻⁵ m

k = dielectric constant of teflon = 2.1

Capacitance is given as

C = \frac{k\epsilon _{o}A}{d}

C = \frac{(2.1)(8.85\times 10^{-12})(0.3304)}{3.1\times 10^{-5}}

C = 1.98 x 10⁻⁷ F

5 0
3 years ago
A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall
Stells [14]
5,658 ft is your answer I believe
6 0
2 years ago
A dragster race car can accelerate from rest to incredible speeds. In one case a dragster is able to finish the 305 m run in 3.6
Dafna1 [17]

Answer:

45.89m/s²

Explanation:

Given

Distance S = 305m

Time t = 3.64s

To get the acceleration during this run, we will apply the equation of motion:

S = ut+1/2at²

Substitute the given parameters into the formula and calculate the value of a

305 = 0+1/2 a(3.64)²

304 = 1/2(13.2496)a

304 = 6.6248a

a = 304/6.6248

a = 45.89m/s²

Hence the average acceleration during this run is 45.89m/s²

4 0
3 years ago
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