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klasskru [66]
3 years ago
15

Seismographs measure the arrival times of earthquakes with a precision of 0.125 s. To get the distance to the epicenter of the q

uake, they compare the arrival times of S- and P-waves, which travel at different speeds. If S- and P-waves travel at 3.74 and 7.22 km/s, respectively, in the region considered, how precisely can the distance to the source of the earthquake be determined
Physics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

435 m

Explanation:

The precision with which the distance to the source of the earthquake can be estimated is equal to the difference in distance covered by the S- and P-waves in the time of 0.125 s.

The distance covered by each type of wave is given by

d=vt

where

v is the speed of the waves

t is the time

For S-waves,

v = 3.74 km/s

t = 0.125 s

So the distance covered is

d_s=(3.74)(0.125)=0.4675 km = 467.5 m

For P-waves,

v = 7.22 km/s

t = 0.125 s

So the distance covered is

d_p=(7.22)(0.125)=0.9025 km = 902.5 m

So, the precision with which the distance can be determined is:

\Delta d = 902.5 - 467.5 =435 m

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Answer:

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Explanation:

We are going to answer the three questions

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5 0
2 years ago
A uniform electric field has a magnitude 1.80 kV/m and points in the +x direction. (a) What is the electric potential difference
EastWind [94]

Answer:

a)ΔV = 6.48 KV

b)ΔU =18.79 mJ

Explanation:

Given that

E= 1.8 KV/m

a)

We know that

Electric potential difference  ΔV given as

ΔV = E .d

Here

E= 1.8 KV/m

d= 3.6 m

ΔV = E .d

ΔV = 1.8 x 3.6 KV

ΔV = 6.48 KV

b)

Given that

q=+2.90 µC

Change in electric potential energy ΔU given as

ΔU = q .ΔV

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igor_vitrenko [27]

Answer:

2.25 billion years

Explanation:

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