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erastova [34]
1 year ago
13

You place a box weighing 242.4 N on an in- clined plane that makes a 37.2° angle with the horizontal. Compute the component of t

he gravita- tional force acting down the inclined plane. Answer in units of N​
Physics
1 answer:
lisabon 2012 [21]1 year ago
6 0

The unit of N is 238.8

What is unit ?

an individual thing or person regarded as single and complete but which can be a also form the an be  individual component of a larger or more complex the  whole.

Sol-On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is mgcos\thetamgcosθ and the component acting down the inclined plane is mgsin\theta.mgsinθ.

It is given that the weight of the block is, mg=  242.N

The angle made with the inclined plane is 37.2°

\Rightarrow mgsin\theta = 242.N N sin 37.2°/^o =238 N⇒mgsinθ=242.N?Nsin42.9

o

=238.8N

Hence, the component of the gravitational force acting down the inclined plane is 238.8 N.

To know more about unit click-

brainly.com/question/25862883

#SPJ9

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At t = 0, object A is dropped from the roof of a building. At the same instant, object B is dropped from a window 10 m below the
dsp73

Answer:

Explanation:

Given two objects are dropped simultaneously

Object A is 10 m higher than object B therefore

Distance covered by object A is given by

y_a(t) is given by

y=ut+\frac{1}{2}at^2

where y=displacement

u=initial velocity

a=acceleration

t=time

y_a(t)=0+0.5gt^2--1

for object B

y_b(t)=0+0.5gt^2--2

Subtract 1 and 2 we get

y_a(t)-y_b(t)=0

i.e. they will travel equal distance in equal time and distance between them remain 10 m until object B hits the ground

           

4 0
3 years ago
A resistor resists the flow of electricity and usually converts electrical energy to heat energy. True or False?
Sidana [21]
Your answer is: True!
7 0
3 years ago
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If two vectors are perpendicular to each other, how should you add them?
Aleksandr [31]

Let us consider two vectors A and B.

As per the question, the two vectors are perpendicular to each other.

Hence the angle between them  \theta =90 degree

We are asked to calculate the resultant of these two vectors.

As per parallelogram law of vector addition, the resultant of two vectors are-

                      R=\sqrt{A^{2}+ B^{2}+2ABcos\theta

                                =\sqrt{ A^{2}+ B^{2}+2AB*cos90}    [cos90=0]

                                =\sqrt{ A^{2}+ B^{2}

This is the way by which we can add two perpendicular vectors.


8 0
3 years ago
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A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field a
Galina-37 [17]

Answer:

E   = (0.56 \times 10^8 ) r   \   \ N/c

Explanation:

Given that:

\rho_o = (10^{-3} ) \ c/m^3

R = (0.1) m

To find  the electric field for r < R by using Gauss Law

{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)

For r < R

Q_{enclosed}=(\rho) ( \pi r^2 ) l

E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}

E= \dfrac{\rho ( r)}{2 \varepsilon_o}

where;

\varepsilon_o = 8.85 \times 10^{-12}

E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}

E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}

E   = (0.56 \times 10^8 ) r   \   \ N/c

4 0
3 years ago
A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?
7nadin3 [17]

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

v_y=9.29\ m/s

Hence, the vertical component of the velocity is 9.29 m/s

3 0
3 years ago
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