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erastova [34]
1 year ago
13

You place a box weighing 242.4 N on an in- clined plane that makes a 37.2° angle with the horizontal. Compute the component of t

he gravita- tional force acting down the inclined plane. Answer in units of N​
Physics
1 answer:
lisabon 2012 [21]1 year ago
6 0

The unit of N is 238.8

What is unit ?

an individual thing or person regarded as single and complete but which can be a also form the an be  individual component of a larger or more complex the  whole.

Sol-On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is mgcos\thetamgcosθ and the component acting down the inclined plane is mgsin\theta.mgsinθ.

It is given that the weight of the block is, mg=  242.N

The angle made with the inclined plane is 37.2°

\Rightarrow mgsin\theta = 242.N N sin 37.2°/^o =238 N⇒mgsinθ=242.N?Nsin42.9

o

=238.8N

Hence, the component of the gravitational force acting down the inclined plane is 238.8 N.

To know more about unit click-

brainly.com/question/25862883

#SPJ9

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3 years ago
A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A
ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is m  =  1612.5  \  kg

Explanation:

From the question we are told that

   The radius of the grinding wheel is R =  0.330 \ m

   The  tangential force is F_t =  250 \ N

    The angular acceleration is  \alpha  =  0.940 \ rad/s^2

The torque experienced by the wheel is mathematically represented as

     \tau  =  I  *  \alpha

Where  I  is the moment of inertia

The torque experienced by the wheel can also be  mathematically represented as

       \tau  =  F_t  * r

substituting values

       \tau  =  250 * 0.330

      \tau  = 82.5  \ N\cdot m

So

   82.5  =  I *  \alpha

    82.5  =  I *  0.940

So

   I  =  87.8 \ kg \cdot m^2

This moment of inertia can be mathematically evaluated as

     I  =  \frac{1}{2} * m* r^2

substituting values

  87.8  =  \frac{1}{2} * m* (0.330)^2

=>   m  =  1612.5  \  kg

5 0
3 years ago
12 seconds after starting from rest a frewly falling cantaloupe has a speed of
adoni [48]

Answer:

<em>The cantaloupe has a speed of 117.6 m/s</em>

Explanation:

<u>Free Fall Motion</u>

It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.

Calculate the final speed:

vf=9.8 * 12 = 117.6 m/s

The cantaloupe has a speed of 117.6 m/s

3 0
3 years ago
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