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erastova [34]
1 year ago
13

You place a box weighing 242.4 N on an in- clined plane that makes a 37.2° angle with the horizontal. Compute the component of t

he gravita- tional force acting down the inclined plane. Answer in units of N​
Physics
1 answer:
lisabon 2012 [21]1 year ago
6 0

The unit of N is 238.8

What is unit ?

an individual thing or person regarded as single and complete but which can be a also form the an be  individual component of a larger or more complex the  whole.

Sol-On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is mgcos\thetamgcosθ and the component acting down the inclined plane is mgsin\theta.mgsinθ.

It is given that the weight of the block is, mg=  242.N

The angle made with the inclined plane is 37.2°

\Rightarrow mgsin\theta = 242.N N sin 37.2°/^o =238 N⇒mgsinθ=242.N?Nsin42.9

o

=238.8N

Hence, the component of the gravitational force acting down the inclined plane is 238.8 N.

To know more about unit click-

brainly.com/question/25862883

#SPJ9

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A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the
Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, \Delta t=0.003\ s

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N

So, the average force on ball by the golf club is 340 N.

4 0
3 years ago
Electric fields are vector quantities whose magnitudes are measured in units of volts/meter (V/m). Find the resultant electric f
musickatia [10]

Answer:

Er = 231.76 V/m, 27.23° to the left of E1

Explanation:

To find the resultant electric field, you can use the component method. Where you add the respective x-component and y-component of each vector:

E1:

E_1_x = 0V/m\\E_1_y=100V/m

E2:

Keep in mind that the x component of electric field E2 is directed to the left.

E_2_x= 150V/m*-sin(45) = 106.07 V/m\\E_2_y=150V/m*cos(45) = 106.07V/m

∑x: E_1_x+E_2_x = 0V/m - 106.07V/m = -106.07V/m

∑y: E_1_y + E_2_y = 100V/m + 106.07V/m = 206.07V/m

The magnitud of the resulting electric field can be found using pythagorean theorem. For the direction, we will use trigonometry.

||E_r||= \sqrt{(-106.07V/m)^2+(206.07V/m)^2} = 231.76 V/m\\\\\alpha = arctan(\frac{206.7 V/m}{-106.07 V/m}) = 117.24degrees

or 27.23° to the left of E1.

8 0
3 years ago
A boy whirls a stone in a horizontal circle of radius 1.4 m and at height 1.5 m above ground level. The string breaks, and the s
balandron [24]

Answer:233.23 m/s^2

Explanation:

Given

radius of circle=1.4 m

Height of stone above ground=1.5 m

Horizontal distance(R)=10 m

It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground

1.5=0+\frac{gt^2}{2}

t=0.55 s

Initial horizontal velocity at the time of break is given by u

R=u\times t

10=u\times 0.55

u=18.07 m/s

Therefore magnitude of centripetal acceleration is given by

a_c=\frac{u^2}{r}=\frac{18.07^2}{1.4}=233.23 m/s^2

6 0
3 years ago
What is the difference between current and voltage besides their units of measurement
kondor19780726 [428]
"Voltage" is the "pressure" that makes electrons want to leave where they are
and head in some direction, if there's conducting material in that direction.

"Current" is the rate at which they all migrate in that direction.
8 0
3 years ago
Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radiu
Gnesinka [82]

The orbiting velocity of the satellite is 4.2km/s.

To find the answer, we need to know about the orbital velocity of a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
  • Mathematically, orbital velocity= √(GM/r)
  • r = radius of the orbital, M = mass of earth
<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
  • M= 5.98×10²⁴ kg, r= 3.57× 6.37×10³ km = 22.7×10⁶m
  • Orbital velocity= √(6.67×10^(-11)×5.98×10²⁴/22.7×10⁶)

=4.2km/s

Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.

Learn more about the orbital velocity here:

brainly.com/question/22247460

#SPJ1

8 0
2 years ago
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