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erastova [34]
1 year ago
13

You place a box weighing 242.4 N on an in- clined plane that makes a 37.2° angle with the horizontal. Compute the component of t

he gravita- tional force acting down the inclined plane. Answer in units of N​
Physics
1 answer:
lisabon 2012 [21]1 year ago
6 0

The unit of N is 238.8

What is unit ?

an individual thing or person regarded as single and complete but which can be a also form the an be  individual component of a larger or more complex the  whole.

Sol-On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is mgcos\thetamgcosθ and the component acting down the inclined plane is mgsin\theta.mgsinθ.

It is given that the weight of the block is, mg=  242.N

The angle made with the inclined plane is 37.2°

\Rightarrow mgsin\theta = 242.N N sin 37.2°/^o =238 N⇒mgsinθ=242.N?Nsin42.9

o

=238.8N

Hence, the component of the gravitational force acting down the inclined plane is 238.8 N.

To know more about unit click-

brainly.com/question/25862883

#SPJ9

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8 0
1 year ago
When is a white dwarf formed?
Anna [14]
When a red giant has insufficient mass it pretty much sheds its outer layer to leave the center core know as the white dwarf
6 0
3 years ago
Read 2 more answers
A single crystal of a metal that has the FCC crystal structure is oriented such that a tensile stress is applied parallel to the
algol13

Stress required to cause slip on in the direction [ 1 1 0 ] is 7.154 MPa

<u>Explanation:</u>

Given -

Stress Direction, A = [1 0 0 ]

Slip plane = [ 1 1 1]

Normal to slip plane, B = [ 1 1 1 ]

Critical stress, Sc = 2.92 MPa

Let the direction of slip on = [ 1 1 0 ]

Let Ф be the angle between A and B

cos Ф = A.B/ |A| |B| = [ 1 0 0 ] [1 1 1] / √1 √3

cos Ф = 1/√3

σ = Sc / cosФ cosλ

For slip along [ 1 1 0 ]

cos λ = [ 1 1 0 ] [ 1 0 0 ] / √2 √1

cos λ = 1/√2

Therefore,

σ = 2.92 / 1/√3 1/√2

σ = √6 X 2.92 MPa = 2.45 X 2.92 = 7.154MPa

Therefore, stress required to cause slip on in the direction [ 1 1 0 ] is 7.154MPa

 

4 0
3 years ago
An athlete whirls a 7.00 kg hammer 1.8 m from the axis of rotation in a horizontal circle, as
iogann1982 [59]

Answer:

A-500 N

Explanation:

The computation of the tension in the chain is shown below

As we know that

F = ma

where

F denotes force

m denotes mass = 7

And, a denotes acceleration

Now for the acceleration we have to do the following calculations

The speed (v) of the hammer is

v = Angular speed × radius

where,

Angular seed = 2 × π ÷ Time Period

So, v = 2 × π × r ÷ P

v = 2 × 3.14 × 1.8 ÷ 1

= 11.304 m/s

Now

a = v^2 ÷ r

= 70.98912 m/s^2

Now the tension is  

T = F = m × a

= 7 × 70.98912

= 496.92384 N

= 500 N

5 0
2 years ago
If Dwight races his Chevy towards Chatham and travels 2460 meters in 60 seconds. what is his velocity?
labwork [276]

Answer:

divide

Explanation:

whenever looking for velocity.just devide

8 0
2 years ago
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