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docker41 [41]
3 years ago
14

What is the size of earth?

Physics
2 answers:
balandron [24]3 years ago
8 0

The  approximate diameter of the earth is equal to 12742 km.

<u>Explanation:</u>

The size of the earth can be explained in many ways. Earth is the third planet from the sun next to mercury and Venus and it is called as natural satellite.

The size of earth in terms of diameter is 12742 km which is almost 1/100th of the size of the sun. The total surface area of the sun is about 510,000,000 km 2.

shtirl [24]3 years ago
4 0

Answer:

Google it

Explanation:

Best if you use google

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What has a higher eccentricity - a planet or a comet?
Daniel [21]

Answer:

comet

Explanation:

hope it helps

7 0
2 years ago
A machine pulls a 46 kg trunk 3.0 m up a 42o ramp at constant velocity, with the machine's force on the trunk directed parallel
Agata [3.3K]

Answer:

the answers are

W = 1271.256 J

E_{th}= 361.81 J

Explanation:

The mass of the trunk (m) = 46kg

angle between the ramp and the horizontal (θ) = 42°

The trunk is pulled at a displacement (d) up the ramp = 3m

The coefficient of kinetic friction between the trunk and the ramp = 0.36

The trunk is moving with a constant velocity therefore the net force on it is zero, therefore the force required to move the trunk must be equal to the summation of forces opposing the trunk

The two forces opposing the trunk are

  1. the gravitational force directed down the ramp  F_{g} and
  2. the frictional force between the ramp and the trunk F_{f}

We have to calculate the machine's force which is equal to sum of the

F =F_{g} + F_{f}

F_{g} = mgsinθ

F_{f} =μ× N

N = mgcosθ

F_{f} = μmgcosθ

F = mg (sinθ + μcosθ)

F = 46× 9.8 (sin42 + 0.36×cos42)

F= 450.8 (0.67 +0.27)

F = 450.8 × 0.94

F = 423.752N

to calculate the workdone on the trunk by the machine force

The workdone on the trunk is  = W = F × dcosΘ

Θ = 0° because the trunk is directed parallel to the ramp

W =423.752× 3 cos 0

W = 423.752 ×3

W = 1271.256 J

(b)  the increase in thermal energy of the trunk and the ramp

Friction converts mechanical energy into thermal energy, so multiplying the frictional force with the distance gives the thermal energy generated by the trunk

E_{th} =F_{f} × d

= μmgcosθ ×d

= 0.36 ×46×9.8×cos42×3

= 361.81 J

5 0
3 years ago
Read 2 more answers
A ray of light travels from a glass-to-liquid interface at an angle of 35.0º. Indices of refraction for the glass and liquid are
UkoKoshka [18]

Answer:

The angle of refraction for the ray moving through the liquid is = 32.3°

Explanation:

Refractive index of liquid (n₁/n₂) = sini/sinr

∴                 n₁/n₂ = sini/sinr ................ equation 1

n₁ = index of refraction for glass, n₂ = index of refraction for liquid

Where i = incident angle of the first medium, r = angle of refraction or angle in the second medium.

Since the light ray is traveling from glass - to - liquid,  the first medium is glass and the second medium is liquid. and the refractive index will be that liquid with respect to glass.

using the equation,

n₁/n₂ = sini/sinr

i = 35° , n₁ = 1.52, n₂= 1.63

Making sinr the subject of the equation above,

sinr = sini/(n₁/n₂)

sinr = sin35(1.52)/1.63

sinr =0.574(1.52)/1.63

sinr = 0.535

Taking the sin inverse of both side of the equation

sin⁻¹(sinr) = sin⁻¹(0.535)

∴ r = 32.3°

The angle of refraction for the ray moving through the liquid is = 32.3°

The right option is (b). 32.3°

5 0
3 years ago
A direct result of the Newlands reclamation Act was the
Lina20 [59]
I think it is building and managing of irrigation systems 
3 0
3 years ago
Read 2 more answers
A mass of 2000 kg. is raised 5.0 m in 10 seconds. What is the potential energy of the mass at this height?
kolbaska11 [484]

Answer:

98,000J

Explanation:

Given parameters :

Mass = 2000kg

Height = 5m

Time = 10s

P. E = mgh

P. E = 2000x 5x 9.8

P.E = 98,000J

5 0
3 years ago
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