Answer:
a)
b)
Explanation:
a) Let's use the constant velocity equation:

- v is the speed of the muon. 0.9*c
- c is the speed of light 3*10⁸ m/s


b) Here we need to use Lorentz factor because the speed of the muon is relativistic. Hence the time in the rest frame is the product of the Lorentz factor times the time in the inertial frame.


v is the speed of muon (0.9c)
Therefore the time in the rest frame will be:



No we use the value of Δt calculated in a)

I hope it helps you!
A child slides down a hill on a toboggan with acceleration of 1.8 m/s2. if she starts from rest, how far has she traveled in: 2 seconds
Answer:
2.4 m
Explanation:
From the question above,
Applying equation of motion,
s = ut+at²/2....................... Equation 1
Where t = time, u = initial velocity, a = acceleration, s = distance.
make s the subject of the equation,
Given: a = 1.8 m/s², t = 2 seconds, u = 0 m/s (from rest)
Substitute these value into equation 1
s = 0(2)+1.8(2²)/2
s = 1.2(4)/2
s = 2.4 m.
Hence she has traveled 2.4 m
The answer is c) electromagnetic sawed in which the vibrations are perpendicular to the motion of the sound
Personal space differs from culture to culture, though it is widely acknowledged that Europe and U.S have bigger personal space requirements that their counterparts in Asia.
Hakeem might not realize it but it’s commonly accepted for Americans to have a distance between four to twelve feet between one another in social settings, especially in professional ones. A distance of two feet is only acceptable if the individual is part of the person’s inner circle, such as friends and family.
Answer:
B. Objects do not have to touch each other to experience a force.
Explanation:
For example ..One of the noncontact forces is magnetic force whereby a magnetic object will be attracted to another magnetic object of oppsite charged particles, through waves called electromagnetic waves. On the other hand, the two magnetic objects of similar charged particles can repel through electromagnetic waves..