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likoan [24]
2 years ago
7

In transverse waves, there is no _________ motion.

Physics
1 answer:
maria [59]2 years ago
4 0

In a transverse wave, the disturbance are carried forward and the particles are undergoing to and fro motion. Hence in transverse waves, there is no horizontal motion.

A wave can be described as a disturbance that travels through a medium from one location to the other location without transporting any matter.

There are two types of matter,

(i) Transverse wave

(ii) Longitudinal wave

In a transverse wave, the particles of the medium move in a direction perpendicular to the direction of propagation of the wave. That means, the particles undergo to and fro motion about their mean position and moves in the direction of the wave propagation.

Examples are:

  • Radio waves
  • Light waves
  • Water waves when a stone is dropped in the pond

Whereas longitudinal waves undergo back and forth motion with respect to the mean position.

To learn more about waves: brainly.com/question/15663649

#SPJ1

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How do i solve for the point of equigravity between two planets, given their mass ratio and the distance between them ?
Dennis_Churaev [7]

The equigravity between two planets is determined from the product and their masses and square of distance between them.

<h3>Gravitational force between two planets</h3>

The gravitational force between two planets is calculated as follows;

F = GM₁M₂/R²

where;

  • G is universal gravitation constant
  • M₁ is mass of first planet
  • M₂ is mass of the second planet
  • R is the distance between the two planets

Use the mass ratio of the two planets to determine their individual masses.

Thus, the equigravity between two planets is determined from the product and their masses and square of distance between them.

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4 0
3 years ago
A flat circular coil having a diameter of 25 cm is to produce a magnetic field at its center of magnitude, 1.0 mT. If the coil h
tresset_1 [31]

Answer:

The current pass through the coil is 6.25 A

Explanation:

Given that,

Diameter = 25 cm

Magnetic field = 1.0 mT

Number of turns = 100

We need to calculate the current

Using the formula of magnetic field

B =\dfrac{\mu_{0}NI}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu N}

Where, N = number of turns

r = radius

I = current

Put the value into the formula

I=\dfrac{1.0\times10^{-3}\times2\pi\times12.5\times10^{-2}}{4\pi\times10^{-7}100}

I=6.25\ A

Hence, The current passes through the coil is 6.25 A

6 0
3 years ago
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