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iren2701 [21]
3 years ago
11

A flat circular coil having a diameter of 25 cm is to produce a magnetic field at its center of magnitude, 1.0 mT. If the coil h

as 100 turns how much current must pass through the coil?
Physics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

The current pass through the coil is 6.25 A

Explanation:

Given that,

Diameter = 25 cm

Magnetic field = 1.0 mT

Number of turns = 100

We need to calculate the current

Using the formula of magnetic field

B =\dfrac{\mu_{0}NI}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu N}

Where, N = number of turns

r = radius

I = current

Put the value into the formula

I=\dfrac{1.0\times10^{-3}\times2\pi\times12.5\times10^{-2}}{4\pi\times10^{-7}100}

I=6.25\ A

Hence, The current passes through the coil is 6.25 A

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Vesnalui [34]

Answer:F=648 N

Explanation:

Given

mass of man m_1=80 kg

mass of Platform m_2=40 kg

acceleration of system a=1 m/s^2

Let F be the force with which man pulls the rope which will also create a tension of F in rope

From Diagram

2F-(m_1+m_2)g=(m_1+m_2)a

2F=(m_1+m_2)(g+a)

F=\frac{(m_1+m_2)(g+a)}{2}

F=\frac{(80+40)(9.8+1)}{2}

F=\frac{1296}{2}

F=648 N

7 0
3 years ago
A pendulum oscillates 40 times in 4 seconds. Find it's time period and frequency.
Elanso [62]

\Large\sf\underline\blue{Question\:given:}

A pendulum oscillates 40 times in 4 seconds. Find it's time period and frequency.

\Large\sf\underline\pink{To~ find:-}

  • The time period
  • Its Frequency

\Large\sf\underline\red{Solution ~1}

Frequency of oscillation is defined as the number of oscillation of a vibrating body per second.It is given by

\sf{Frequency=}  \\ \dfrac{Number ~of~ oscillation}{Time}

=\dfrac{40}{4}

\sf{=10 Hz}

\Large\sf\underline\green{Solution ~2}

The time period

The time required to complete one oscillation is known as Time period.

It is given by the inverse of the frequency.

\sf{Time~Period=} \\ \dfrac{1}{Frequency ~of~ oscillation}

{=}\dfrac{1}{10}

\sf{=0.1 s}

________________

Therefore the frequency is \sf{=10 Hz}

And the time period is \sf{=0.1 s}

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5 0
3 years ago
Two masses, each weighing 1.0 × 103 kilograms and moving with the same speed of 12.5 meters/second, are approaching each other.
pav-90 [236]

Answer:

A. 1.6 × 105 joules

Explanation:

As per the question, the data given in the question is as follows

Number of masses = 2

Each weightage = 1.0 \times 2.3

Speed = 12.5 meters/ second

Based on the above information, the approximate kinetic energy after the collision is

A perfectly elastic collision is described as one where the collision does not cause any loss of kinetic energy. 

So we sum the kinetic energy of each kind of system which is given below:

Kinetic energy is

= 0.5(1.0 \times 10^3) (12.5)^2 + 0.5 (1.0 \times 10^3) (12.5 )^2

= 156250 J

= 1.6 \times 10^5 J

8 0
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If you observe closely, you will notice that the particles leave a trail behind them as they move. The longer the trail, the fas
beks73 [17]

Answer:

when there is a change in the direction

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8 0
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Which force is responsible for allowing carbon-14 to become stable? *
Bas_tet [7]

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