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MariettaO [177]
3 years ago
15

To make and sell fireplaces, Hearth, Inc., buys igniters, tubing, and other parts from Inflame Parts and installs them without m

odification. If the parts are defective, strictly liable for any damage caused by the defects. What is the wavelength of the light used in this experiment?
Physics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

Infrared Wavelength

Explanation:

It is because the most long range wavelength i n this case will be the infrared wavelength that has a heating effect on bodies when exposed for a longer period of times. Similarly, the visible wavelength of light is also involved. The defective parts in the fireplace will allow the escape of these infrared wavelength radiations. This heating effect can cause fire near the fire place where the defective fireplace is placed without modifications.

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A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refrac
elena55 [62]

Answer:

A

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1.  So:

1 sin 30° = 1.52 sin θ

θ ≈ 19°

5 0
3 years ago
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
KatRina [158]

Answer:

E = kQs/r.r

Explanation:

Where E is the magnitude of electric field...

k is called Columb's Constant. It has a value of 8.99 x 109 N m2/C2.

Qs is the magnitude of the source charge...

and r is the magnitude of distance between source and target...

(When electron comes to rest Δt the magnitude of Electric field E become zero momentarily but later achieves the maximum value...)

5 0
3 years ago
Your friend, Tim, is playing with his sled. He ties a rope to his sled and attaches it to Lar's snowmobile. Tim has a mass of 71
kykrilka [37]

The maximum speed of Tim is 16.95 m/s.

The given parameters:

  • Mass of the rope, m = 71 kg
  • Tension on the rope, T = 220 N
  • Coefficient of kinetic friction, = 0.1
  • Time of motion, t = 8 s

<h3>What is Newton's second law of motion?</h3>
  • Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on Tim is calculated by applying Newton's second law of motion as follows;

T - \mu _k F_n = ma\\\\T - \mu _k F_n = m\frac{v}{t} \\\\T - \mu_k mg = m\frac{v}{t} \\\\t(\frac{T - \mu_k mg}{m} )= v\\\\8 (\frac{220 \ -\  0.1 \times 71 \times 9.8}{71} ) =v \\\\ 16.95 \ m/s = v

Thus, the maximum speed of Tim is 16.95 m/s.

Learn more about net horizontal force here: brainly.com/question/21684583

7 0
2 years ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

J=\frac{E}{\rho}      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

J=\frac{I}{A}        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}

Next, you replace for all variables:

I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A

hence, the current in the wire is 4.75A

4 0
3 years ago
Inside a television picture tube there is a build-up of electrons (charge of 1. 602 × 10–19 C) with an average spacing of 38. 0
Olin [163]

The magnitude of the electric field inside the picture tube is 998.476 kN/C.

<h3>What is an electric field?</h3>

It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,

E =\dfrac {kQ}{r^2 }

Where,

E = electric field produced

Q = charge =  1.602 \times  10^{-19}\rm \  C

r = distance = 38 \times  10^{-9}\rm \  m

k = Coulomb's constant = 9 \times 10^9 \rm \ N. m2 / C2

Put the values in the formula,

E = \dfrac {9 \times 10^9\times 1.602 \times  10^{-19}}{(38 \times  10^{-9})^2}\\\\E = 998.476 \rm \ kN/C

Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.

Learn more about the electric field:

brainly.com/question/3783640

8 0
2 years ago
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