7 and a half hours because if you multiply 120 by 8 you get 960 and if you multiply 120 by 7 you get 840. So it’ll take 7 full hours and 30 minutes to reach 950 km. Hope this helps and I’m sorry if it’s wrong I did my best :)
Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V
C1= 3×10^-6 F
V1= 480v
C2= 4×10^-6 F
V2= 500v
(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V
Simplifying the above, we get:
( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.
Further simplified as:
3440 × 10^-6 = 7 × 10^-6 × V
Making V the subject
V = 491.43volts
Therefore the potential difference across each capacitor is 491.43v
Answer:
speed of masses after collision = 2m/s
Explanation:
Using the formula for inelastic collision;
m1u1 + m2u2 = (m1+m2)v
Where m1 is mass of body 1
m2 is mass of body 2
u1 is initial velocity of body 1
u2 is initial velocity of body 2
v is final velocity
m1 =2kg , u1=5m/s , m2=3kg, u2=0(body at rest) v=?
(2*5) + (3*0)= (2+3)v
10=5v
v = 10/5
v=2m/s
Answer:
(a)
(b) 157.76679 m
(c) 17.62757 m/s
Explanation:
Net force acting,
Acceleration, where m is the mass
(b)
From kinematic equation
where s is displacement, u is initial velocity, t is time taken and a is acceleration.
Considering that u=0 since it starts at rest
and substituting the value of a as calculated in part a, t is 17.9 s hence
(c
)
From kinematic equation
v=u+at where u and v are initial and final velocities respectively, a is acceleration and t is duration in seconds. Since it starts from rest, u=0 and substituting the value of a as found in part a, t given as 17.9 s we get
V=0+0.984781*17.9=17.62757 m/s