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morpeh [17]
3 years ago
9

I need help on 5 ONLY

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

$8.75

Step-by-step explanation:

$1.25*3=$3.75

$2.50*2=$5.00

Add $3.75 and $5.00 for a total of $8.75

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Answer:

B

Step-by-step explanation:

To find the distance we need to add the numbers:

2 - (-3/4) = 2 + 3/4

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The length of the red line segment is 6, and the length of the blue line segment is 4. how long is the major axis of the ellipse
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An ellipse is divided into two axes, the longer axis is the major axis and the shorter axis is the minor axis. The length of the major axis of an ellipse is equal to the sum of two distance: the distance between any point on the ellipse and one on focus and the distance between the same point and the other focus. The focus is the point that helps define an ellipse and every ellipse has two foci. These two distance are also called the red line segment and blue line segment. Given 6 for red line segment and 4 for blue line segment therefore, the length of the major axis of the ellipse is 10.

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Nah fam math hard math can solve its own problems 82773919
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2 years ago
What is n-9 divided by 10=-2
DerKrebs [107]

The value of n is 11.

<u>Step-by-step explanation</u>:

The given expression is (n-9) ÷ 10 = -2

<u>To find the value of n</u> :

  • From the expression, it is determined that (n-9) is the numerator and 10 is the denominator.
  • Cross multiply the denominator in the left side of the expression to the another side.

The expression becomes (n-9) = (10\times -2).

⇒ n-9 = -20

Keep the n term on one side and the constants on other side.

⇒ n = -20+9

⇒ n = -11

Therefore, the value of n is 11.

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natta225 [31]

Answer:

a) 99% of the sample means will fall between 0.933 and 0.941.

b) By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

(a) If the true mean is 0.9370 with a standard deviation of 0.0090 within what interval will 99% of the sample means fail?

Samples of 34 means that n = 34

We have that \mu = 0.937, \sigma = 0.009

By the Central Limit Theorem, s = \frac{0.009}{\sqrt{34}} = 0.0015

Within what interval will 99% of the sample means fail?

Between the (100-99)/2 = 0.5th percentile and the (100+99)/2 = 99.5th percentile.

0.5th percentile:

X when Z has a pvalue of 0.005. So X when Z = -2.575.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2.575 = \frac{X - 0.937}{0.0015}

X - 0.937 = -2.575*0.0015

X = 0.933

99.5th percentile:

X when Z has a pvalue of 0.995. So X when Z = 2.575.

Z = \frac{X - \mu}{s}

2.575 = \frac{X - 0.937}{0.0015}

X - 0.937 = 2.575*0.0015

X = 0.941

99% of the sample means will fall between 0.933 and 0.941.

(b) If the true mean 0.9370 with a standard deviation of 0.0090, what is the sampling distribution of ¯X?

By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

6 0
3 years ago
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