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Arte-miy333 [17]
2 years ago
13

You connect a 9V battery to a capacitor consisting of two circular plates of radius 0.066 m separated by an air gap of 2.0 mm. W

hat is the charge on the positive plate?
Physics
1 answer:
mel-nik [20]2 years ago
3 0

The charge on the positive plate is 1.734*10^{-12} C

Given,

V=9v, R=0.066m Gap(G)=2.0mm=0.0020m ∈=8.85*10^{-12}

We know C=∈ * \frac{A}{G}= 8.85*10^{-12} *\frac{\pi *0.066^{2} }{0.002}=19.275*10^{-12} F

Also, Q = C V = 19.275*10^{-12} * 9 = 1.734*10^{-12} C

<h3>Charge </h3>

When charged matter is exposed to an electromagnetic field, its electric charge—a property of matter—causes it to feel a force. A charge on an electric field might be positive or negative. Like and unlike charges are attracted to one another while being repelled by the other. Neutral describes a thing without any net charge. Electric charge is a conserved property; in an isolated system, the net charge, or the sum of the positive and negative charges, is constant. Subatomic particles transport electrical charge. The protons in atoms' nuclei carry positive charge in normal matter, while the electrons carry negative charge.

Learn more about charge here:

brainly.com/question/19886264

#SPJ4

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the focal length of a simple magnifier is 8.50 cmcm . assume the magnifier to be a thin lens placed very close to the eye.
Igoryamba

When the object is at the focal point the angular magnification is 2.94.

Angular magnification:

The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.

Here we have to find the angular magnification when the object is at the focal point.

Focal length = 6.00 cm

Formula to calculate angular magnification:

Angular magnification = 25/f

                                            = 25/ 8.5

                                             = 2.94

Therefore the angular magnification of this thin lens is 2.94

To know more about angular magnification refer:: brainly.com/question/28325488

#SPJ4

5 0
1 year ago
The flywheel is rotating with an angular velocity ω0 = 2.37 rad/s at time t = 0 when a torque is applied to increase its angular
nika2105 [10]

Answer:

ω = 12.023 rad/s

α = 222.61 rad/s²

Explanation:

We are given;

ω0 = 2.37 rad/s, t = 0 sec

ω =?, t = 0.22 sec

α =?

θ = 57°

From formulas,

Tangential acceleration; a_t = rα

Normal acceleration; a_n = rω²

tan θ = a_t/a_n

Thus; tan θ = rα/rω² = α/ω²

tan θ = α/ω²

α = ω²tan θ

Now, α = dω/dt

So; dω/dt = ω²tan θ

Rearranging, we have;

dω/ω² = dt × tan θ

Integrating both sides, we have;

(ω, ω0)∫dω/ω² = (t, 0)∫dt × tan θ

This gives;

-1[(1/ω_o) - (1/ω)] = t(tan θ)

Thus;

ω = ω_o/(1 - (ω_o × t × tan θ))

While;

α = dω/dt = ((ω_o)²×tan θ)/(1 - (ω_o × t × tan θ))²

Thus, plugging in the relevant values;

ω = 2.37/(1 - (2.37 × 0.22 × tan 57))

ω = 12.023 rad/s

Also;

α = (2.37² × tan 57)/(1 - (2.37 × 0.22 × tan 57))²

α = 8.64926751525/0.03885408979 = 222.61 rad/s²

6 0
3 years ago
At which location would you expect the LOWEST TEMPERATURE?
MissTica

Answer:

c

Explanation:

3 0
3 years ago
Read 2 more answers
The model of the universe that suggests that the sun is the center of the universe was first brought by
gladu [14]
I think the correct answer from the choices listed above is option D. The model of the universe that suggests that the sun is the center of the universe was first brought by Copernicus. His model is known as the "Sun centered model".
5 0
4 years ago
Read 2 more answers
A rigid, uniform bar with mass mmm and length bbb rotates about the axis passing through the midpoint of the bar perpendicular t
Pie

Answer:

I = \frac{mvb}{6}

Explanation:

we know angular velocity in terms of moment of inertia and angular speed

       L = Iω ....                        (1)

moment of inertia of rod rotating about its center of length b

 

      I = \frac{ mb^2}{12}  ........               .(2)  

using         v = ωr  

where w is angular velocity

and r is radius of  rod which is equal to b

        so we get  2v =  ωb  

                            ω  = 2v/b  .................            (3)    

here velocity is two time because two opposite ends  are moving opposite with a velocity v so net velocity will be 2v

put second and third equation in ist equation

                 L   =   \frac{mb^2}{12}×\frac{2v}{b}

              so final answer will be      L  =   \frac{mvb}{6}

7 0
3 years ago
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