Answer:
The magnitude of the electric field is 8.47 N/C
Explanation:
Given;
uniform charge density, λ = 100 nC/m³
inner radii of the cylinder, r = 1.0 mm and 3.0 mm
distance from the symmetry axis, R = 2.0 mm
Area = 2πrl
Area =2π(2 x 10⁻)l
Volume = A x d
d = Volume / Area
the magnitude of the electric field
Therefore, the magnitude of the electric field is 8.47 N/C
Answer:
Using the relation V^2 = U^2 + 2× a× S
V^2 = 50^2 + (2× 5 × 240 )
V^ 2 = 2500 + 2400
V^ 2 = 4900
V= (4900)^0.5 = 70 m/s
hence, velocity at a distance of 240 m will be 70m/s.
Now using the relation,
V= U + a× t
70 = 50 + 5 × t
20 = 5 × t
t = 20/5 = 4m/s
hence , time required to travel a distance of 240m will be 4s.
It will float because the density is less than 1
Answer:
36 joule
Explanation:
The formula of kinetic energy is 1/2 mv2.