The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.
so airspeed due west is = net speed - speed of plane = 240-220= 20 km/h.
airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.
the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h
the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.
if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.
so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.
the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.
Answer:
The vulture loses 6.1 m height
Explanation:
Please see the attached figure.
The horizontal distance and the loss of height form a 90º triangle.
The loss of height is the side opposite the given angle (3.5º) and the 100 m horizontal distance is adjacent the angle.
Then, using trigonometric rules:
(1) sin 3.5º = h / hyp
(2) cos 3.5º = distance / hyp
where
h = height lost during the flight.
hyp = hypotenuse of the triangle
Using (2) we can calculate the hypotenuse:
cos 3.5º = 100 m / hyp
hyp = 100 m / cos 3.5º = 100.2 m
with the hypotenuse we can now calculate the loss of height using (1):
sin 3.5º = h / hyp
sin 3.5º = h / 100.2 m
sin 3.5º * 100.2 m = h
<u>h = 6.1 m</u>
( very modest drop in height indeed!)
Answer:
Hey, I'm not sure I understand exactly what your assignment is but hopefully this helps . . .
put the other end against the side of the bubls base to light up the light bulb.
This will act as the bulbs conductor, lighting up bc you are making a complete electrical circuit between positive and negative terminals of the battery.
Ok hopefully this helps you out
