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faust18 [17]
3 years ago
8

Which of the following is the best example of a good hypothesis?

Physics
2 answers:
Musya8 [376]3 years ago
4 0

Answer:

Which of the following is the best example of a good hypothesis?

B. A cheetah can run faster than a tiger This Is A good Hypothesis Because You Can Test this With a Experiment

xXxAnimexXx

Have a great day!

wlad13 [49]3 years ago
4 0

Answer:

B. A cheetah can run faster than a tiger.

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Which object has the greatest amount of kinetic energy?
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I think that the answer is A
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What are the dimensions of potential energy?​
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Potential Energy (P.E) = Mass x

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Potential energy= M1L2T-2.

5 0
3 years ago
When discussing distances between objects in the solar system, which term do you use?
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I think it's (ASTRONOMICAL UNIT)

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2 years ago
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A turntable that is initially at rest is set in motion with a constant angular acceleration α. What is the magnitude of the angu
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Explanation:

If the turntable starts from rest and is set in motion with a constant angular acceleration α. Let \omega is the angular velocity of the turntable. We know that the rate of change of angular velocity is called the angular acceleration of an object. Its formula is given by :

\alpha =\dfrac{\omega_f-\omega_i}{t}

\alpha =\dfrac{\omega-0}{t}

\alpha =\dfrac{\omega}{t}

t=\dfrac{\omega}{\alpha }............(1)

Using second equation of kinematics as :

\theta=\omega_i t+\dfrac{1}{2}\alpha t^2

\theta=\dfrac{1}{2}\alpha t^2

Using equation (1) in above equation

\theta=\dfrac{1}{2}\times \dfrac{\omega^2}{\alpha }

In one revolution, \theta=4\pi (in 2 revolutions)

4\pi =\dfrac{1}{2}\times \dfrac{\omega^2}{\alpha }

\omega=\sqrt{8\pi \alpha}

\omega=2\sqrt{2\pi \alpha}

Hence, this is the required solution.

6 0
4 years ago
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If two ends A and B are connected through a metallic wire. If electrons flows from point B to point A. What can you say about th
Ivan

Answer:

Point A is at higher potential than point B

Explanation:

Electrons are negatively charged - this means that they are attracted by positive charges and repelled by negative charges.

This also means that they tend to move in a direction opposite to the electric field lines (because electric field lines point away from a positive charge and toward a negative charge). So, they also tend to move from a point at lower potential to a point at higher potential.

In this problem, the electrons flow from point B to point A: therefore, point A must have higher potential than point B.

6 0
3 years ago
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