Bicyclist initial kinetic energy is Ek=(1/2)*m*v² where m is his mass and v is his speed and that is equal to:
Ek=(1/2)*60*2²=120 J.
When we add the increased work output, we get the total kinetic energy:
Ek(total)=Ek+W= 120 J + 1800 J= 1920 J
So Ek(total)=1920 J = (1/2)*m*V² where V is the speed after the bicyclist increased his work output. So lets solve for V:
(1/2)*60*V²=1920
30*V²=1920, we divide by 30,
V²=64, and take the square root of both sides,
V=8 m/s.
So the speed of the bicyclist after the increased work output is V=8 m/s.
Answer:
The answer is D.
Explanation:
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Answer:
hub moon merc saturn sun galaxy deep field
Explanation:
Answer:
53 kg m/s
Explanation:
Momentum = mass × velocity
p = mv
p = (8.9 kg) (6.0 m/s)
p = 53.4 kg m/s
Rounded to 2 significant figures, the momentum is 53 kg m/s.
Answer:
= 19.32 m/s and
= 27.32 m/s
Explanation:
The kinetic energy has as formula
K = ½ m v²
Where m is the mass and v the speed of the body.
If the policeman calculates the kinetic energy, let's clear the speed
v = √ 2K/m
Let's reduce the units to the SI system
K = 16.32 KJ (1000 J / kJ) = 16.32 10³ J
Let's calculate
v = RA (2 16.32 10 3/60)
v = 23.32 m / s
The rider at 14.4 km/h, reduce
= 14.4 km / h (1000m / 1km) (1h / 3600s) = 4.00 m / s
We already have the relative speed of the two (rider and police car) which is 23.32, we also have the rider speed 4.0 m / s, let's calculate the possible police speeds
These two speeds come from going in the same direction or in opposite directions
=
±
=
- vj
= 23.32 - 4
= 19.32 m/s
=
+ vj
= 23.32 +4
= 27.32 m/s