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spin [16.1K]
2 years ago
14

At Farmer Jones Market, bananas cost $.80 per pound. At Farmer Garcia's

Mathematics
1 answer:
e-lub [12.9K]2 years ago
4 0

divide $4.50 by 5 .......

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What is the opposite of -45?
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Look at the figure, FHJM. find the length of HJ​
Nat2105 [25]

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HJ=42\ m

Step-by-step explanation:

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The figure FHJM is a parallelogram

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3 years ago
F(x) = x2. What is g(x)?
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Answer: g(x)=. Step-by-step explanation: We are given that: f(x)=x². We have to find g(x). Since, we are given that g(3)=1. Hence, we will ...  ·  g of x would equal (1/3x)^2 because if x was 6 y, g(x), would be 4

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6 0
2 years ago
A sample of 38 observations is selected from one population with a population standard deviation of 3.4. The sample mean is 100.
kaheart [24]

Answer:

a. two-tailed test

b. reject H0 if Z>1.96 or Z<-1.96

c. Z = 1.73

d. we have failed to reject the null hypothesis

e. P-value = 0.0418

Step-by-step explanation:

We will use a Z test to resolve this, an it will be a two-tailed test because the hypothesis statements are not indicating a specific direction for the significant difference (H0 : μ1 = μ2 ; H1 : μ1 ≠ μ2), this also means that the significanclevel will be divided between the both tails (2.5% en each tail for the rejection regions). See attached drawing for reference.

We need to find our critical value:

Zα/2 = Z(0.05/2) = 0.025

If we look for 0.025 in a Z table we will find that the critical value is 1.96 to the right, and by symmetry -1.96 to the left. So our decision rule will be to reject H0 if Z>1.96 or Z<-1.96

The Z test will be done using the next equation:

Z = (x⁻1 - x⁻2) - (μ1 - μ2) / √( σ²1/n1 + σ²2/n2

Because we are testing the null hypothesis we know that μ1 - μ2 must be zero if they are supposed to be equal (H0 : μ1 = μ2), so we calculate as follows:

Z = (100.5 - 98.8) - (0) / √( (3.4)²/38 + (5.8)²/51 = 1.7/0.9817 = 1.73

Z<1.96, therefore we have failed to reject the null hypothesis

The P-value for this test would be represented by the probability of Z being greater than 1.73, so we can look for it in any Z table, finding that its value is 0.0418, and because P-value>0.025 we again confirm that we don't have evidence statistically significant to reject the null hypothesis

4 0
3 years ago
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