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2 years ago

Compared to humans, elephants have a dramatically low instance of cancer. Elephants have multiple copies of the

Biology

1 answer:

Yanka [14]2 years ago

6 0

Elephants have multiple copies of the p53 genes that play an important role in the control of cell division.

<h3>What is the role of p53 genes in elephants?</h3>

P53 is an important regulator of the DNA repair processes and controls uncontrolled cell proliferation. When DNA is harmed, the protein becomes active and aids in orchestrating a response that stops DNA replication and fixes any incorrect copies of the cell. The oncogene MDM2 E3 ubiquitin ligase, another protein, is responsible for deactivating the p53 repair activity in duplicated cells with intact DNA since it is not required.

A human with only two alleles from a single gene has much fewer molecular anti-cancer interactions than an elephant, which has 40 alleles, or versions, from its twenty p53 genes. Although the elephant may appear to have excessive genetic diversity, each of its 40 alleles is structurally slightly different.

I understand the question you are looking for is this:

Compared to humans, elephants have a dramatically low instance of cancer. Elephants have multiple copies of the _____ genes that play an important role in the control of cell division.

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Which of the following is true concerning mangrove forests?

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Explanation:

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________ reactions require energy to synthesize large molecules from small molecules.

denis-greek [22]

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<h3>What is a catabolic reaction?</h3>

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1 year ago

Brown spotting of the teeth in humans is caused by a dominant X-linked gene. If a man with normal teeth marries a woman with bro

nata0808 [166]

Answer:

25%

Explanation:

The female with brown teeth had a father with normal teeth. Since normal teeth is a recessive trait, the father would have been homozygous recessive for the trait and would have transmitted one recessive allele to the female. Therefore, the female is heterozygous dominant for brown teeth.

Let's assume that the allele for brown teeth is X^B while the one for normal teeth is X^b. The genotype of heterozygous dominant female would be X^BX^b and that of the male with normal teeth would be X^bY.

A cross between X^BX^b and X^bY gives progeny in following phenotype ratio= 1/4 daughter with brown teeth: 1/4 daughter with normal teeth: 1/4 son with brown teeth: 1/4 son with normal teeth. Therefore, the probability of having a daughter with brown teeth is = 25%

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3 years ago

What are the general features of organic compounds?

kolezko [41]

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3 years ago