Which equation represents a population of 490 animals that decreases at an annual rate of 20% ?
1 answer:
The equation which represents a population of 490 animals that decreases at an annual rate of 20% is;
When the input variable x appears as an exponent in the formula the exponential function is indicated.
The exponential curve is influenced by both the exponential function and thus the value of x.
where, a = initial value.
b = 1 + r (rate of increase or decrease)
The animals' original population is indicated here by: 490
Thus, a = 490
Additionally, 20% is the rate of increase.
So, r = 20%
r = 0.20
As a result, the population function, or the number of animals in a population, is as follows:
To know more about the exponential function, here
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<h3>Answer:</h3>
y=-5x-2
<h3>Solution:</h3>- We are given the line's slope and a point that it passes through.
- Using the given information, we can write the equation of the line in Point-Slope Form:
- In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
- In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
- Plug in the values:
- y-(-12)=-5(x-2)
- y+12=-5(x-2)
- Now, convert into Slope-Intercept Form, y=mx+b:
- y+12=-5x+10
- y=-5x+10-12
- y=-5x-2
Hope it helps.
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