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bearhunter [10]
3 years ago
6

The slope on a distance-time graph shows a ball moving from 20 m to 40 m in 1 s and from 40 m to 80 m in the next second. Which

describes the ball’s motion between 20 m and 80 m on the graph?
Physics
2 answers:
sergij07 [2.7K]3 years ago
6 0

slope of the graph on first part of the motion

slope = \frac{\Delta x}{\Delta t}

slope = \frac{40 - 20}{1}

slope = 20

for next part of motion similarly

slope = \frac{\Delta x}{\Delta t}

slope = \frac{80 - 40}{1}

slope = 40

so this shows the slope of the motion is not same during two interval of time

it shows that the velocity of the motion is not constant and increasing here with time

SO this shows and accelerated motion from initial to final and the overall slope of the motion is given by

slope = \frac{\Delta x}{\Delta t}

slope = \frac{80 - 20}{2}

slope = 30

stellarik [79]3 years ago
3 0
45 is the correct answer
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An input force is a Push or pull that ________________________ to the machine
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is applied to

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8 0
4 years ago
A circular space station of radius 100 m rotates twice each minute.
Gennadij [26K]

The space station completes 2 revolutions each minute, so that it traverses a distance of 2<em>π</em> (100 m) = 200<em>π</em> m each minute, giving it a linear/tangential speed of

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(a) The astronaut would experience an acceleration of

<em>a</em> = <em>v</em> ² / (100 m) ≈ 1.09662 m/s² ≈ 0.1119<em>g</em> ≈ 0.11<em>g</em>

<em />

(b) Now you want to find the period <em>T</em> such that <em>a</em> = <em>g</em>. This would mean the astronaut has a tangential speed of

<em>v</em> = (200<em>π</em> m) / <em>T</em>

so that her centripetal/radial acceleration would match <em>g</em> :

<em>a</em> = <em>g</em> = ((200<em>π</em> m) / <em>T </em>)² / (100 m)

Solve for <em>T</em> :

(100 m) <em>g</em> = (400<em>π</em> ² m²) / <em>T</em> ²

<em>T</em> ² = (400<em>π</em> ² m²) / ((100 m) <em>g</em>) = (4<em>π</em> ² m)/<em>g</em>

<em>T</em> = √((4<em>π</em> ² m) / (9.8 m/s²)) ≈ 2<em>π</em> √(0.102 s²) ≈ 2.007 s ≈ 2.0 s

3 0
3 years ago
A city of punjab has 15 percemt chance of wet weather on any given day. What is probability that it will take a week for it thre
sesenic [268]

Answer:

The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447

Explanation:

We are given that A city of Punjab has 15 percent chance of wet weather on any given day.

So, Probability of wet weather = 0.15

Probability of not being a wet weather = 1-0.15 =0.85

We are supposed to find probability that it will take a week for it three wet weather on 3 separate days

Total number of days in a week = 7

We will use binomial over here

n = 7

p =probability of failure = 0.15

q = probability of success=0.85

r=3

Formula :P(r=3)=^nC_r p^r q ^{n-r}

P(r=3)=^{7}C_{3} (0.15)^3 (0.85)^{7-3}\\P(r=3)=\frac{7!}{3!(7-3)!} (0.15)^3 (0.85)^{7-3}\\P(r=3)=0.06166

Standard deviation =\sqrt{n \times p \times q}

Standard deviation =\sqrt{7 \times 0.15 \times 0.85}

Standard deviation =0.9447

Hence The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447

4 0
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