Answer:

Explanation:
Given that
Length= 2L
Linear charge density=λ
Distance= d
K=1/(4πε)
The electric field at point P



So

Now by integrating above equation

Waves transmit energy without transmitting matter, This means that we can move energy or information from one place to another without moving any substance from one place to another.
The height at time t is given by
h(t) = -4.91t² + 34.3t + 1
When the ball reaches maximum height, its derivative, h'(t) = 0.
That is,
-2(4.91)t+34.3 = 0
-9.82t + 34.3 = 0
t = 3.4929 s
Note that h''(t) = -9.82 (negative) which confirms that h will be maximum.
The maximum height is
hmax = -4.91(3.4929)² + 34.3(3.4929) + 1
= 60.903 m
Answer:
The ball attains maximum height in 3.5 s (nearest tenth).
The ball attains a maximum height of 60.9 m (nearest tenth)
Answer:
Trophosphere
Explanation:
The troposphere is the atmospheric layer closest to the planet and is characterized because contains the largest percentage of the mass of the total atmosphere.
On special characteristic is that in this layer the temperature and water vapor content decrease a lot respect to the altitude. Also on this layer the Water vapor is important in order to regulate the air temperature since on this zone we have absorption of the solar energy.
The troposphere contains almost all the water vapor in the atmosphere. And specially on the tropics we have an accumulation of the water vapour.
All weather phenomena occur within the troposphere. Tropos means "change" and Troposphere means "region of mixing".
Above this layer, we have the tropopause, ranges in height from 5 miles near the poles up to 11 miles above the equator. And the height depends of the seasons, with an special characteristic: the is highest height occurs in the summer and lowest height occurs in the winter.
The troposphere contains almost 75% of the mass of the entire atmosphere. The air on this layer is composed by 78% nitrogen, 21% oxygen and 1% is made of argon, water vapor, and carbon dioxide.
So for this reason this is the Region that contains the majority of molecules in the atmosphere.
Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of

, and a mass of

. So, the number of protons is

And so the total charge of these protons is

So, the neutralize this charge, we must have

electrons such that their total charge is

Since the charge of each electron is

, the number of electrons needed is

which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is

, the total mass of electrons should be