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3 years ago

The Earth's magnetic field protects the planet from _____.

Physics

1 answer:

OLga [1]3 years ago

8 0

The answer you're looking for is the last option. "ultraviolet radiation." Hope this proves helpful!

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In your own words, explain what conservation of energy means. Also, give an example of the conservation of energy using somethin

Genrish500 [490]

Energy can not be created or destroyed but can change from one form to another.

example: as a roller coaster cart loses height the more speed it gains, the potential energy is transferred into kenetic energy

8 0

3 years ago

A diagnostic sonogram produces a picture of internal organs by passing ultrasound through the tissue. In one application, it is

miss Akunina [59]

Answer:

1) $\lambda = 11\times 10^{-4} m$

2) $2.51\times 10^9 Pa$

Explanation:

Given data:

speed of sound v = 1540 m/s

frequency f = 1.40 MHz = 1.40 \times 10^6 Hz

density $\rho = 1060 kg/m^3$

1) we know that

$v = f\lambda$

$\lambda = \frac[v}{f} = \frac{1540}{1.40\times 10^6}$

$\lambda = 11\times 10^{-4} m$

2) we know that

$v= \sqrt{\frac{modulus}{density}}$

$v^2 = \frac{\gamma}{\rho}$

$\gamma = v^2 \rho$

$\gamma = 1540^2 \times 1060 = 2.51 \times 10^9 Pa$

6 0

4 years ago

A sandbag motionless in outer space is hit by a three-times-as massive sandbag moving at 12 m/s. They stick together. This is an

vekshin1

Answer:

This is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

Explanation:

Let the mass of the motionless sandbag = m₁

Let the mass of the moving sandbag = m₂ = 3m₁

initial velocity of the motionless sandbag, u₁ = 0

initial velocity of the moving sandbag, u₂ = 12 m/s

Let their final velocity, = v

Collision between two particles can either be elastic or inelastic.

Since they stick together after the impact, then the collision is inelastic

Apply the principle of conservation of linear momentum;

Initial kinetic energy = final kinetic energy

¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂v²(m₁ + m₂)

¹/₂m₁(0)² + ¹/₂(3m₁)(12)² = ¹/₂v²(m₁+3m₁)

216m₁ = 2m₁ v²

v² = 108

v = √108

v = 10.392 m/s

Change in kinetic energy = Final kinetic energy - initial kinetic energy

Initial Kinetic energy, KE₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

KE₁ = ¹/₂m₁(0)² + ¹/₂(3m₁)(12)²

KE₁ = 216m₁ J

Final kinetic energy, KE₂ = ¹/₂v²(m₁ + m₂)

KE₂ = ¹/₂(108)(m₁ + 3m₁)

KE₂ = 216m₁ J

ΔKE = KE₂ - KE₁ = 216m₁ J - 216m₁ J = 0%

Therefore, this is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

4 0

3 years ago

It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone?

zepelin [54]

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

$Work=Power\times time$

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

$Work=342J/s\times 59s=20178J$

Thus the work done on the flagstone is 20178 J

5 0

3 years ago

TRUE OR FALSE <br> The nearby galaxy in the spectrum below is moving toward the close star.

katen-ka-za [31]

Answer:

i think its false tell me if im wrong

Explanation:

5 0

4 years ago