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Anon25 [30]
1 year ago
7

Find the length of the semi-major axis of the ellipse x^2/49+y^2/36=1

Mathematics
1 answer:
Slav-nsk [51]1 year ago
4 0

The length of the semi-major axis of the ellipse is 7.

What is the semi-major axis of an ellipse?

The semi-major axis of an ellipse is the half of the longest diameter passing through its vertex and focus.

The general equation of an ellipse is :

⇒ x²/a²+y²/b²=1, where a is the semi-major axis and b, is the semi-minor axis

x²/49+y²/36=1

x²/(7²)+y²/(6²)=1

x²/a²+y²/b²=1

a=7

Learn more about the semi-major axis here:

brainly.com/question/14180045

#SPJ1

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Step-by-step explanation:

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3 years ago
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4x + y = 10<br> 7x + 2y = 17
Nezavi [6.7K]

Answer:

x = 3, y = - 2

Step-by-step explanation:

By substitution method,

4x + y = 10 -------> equation 1.

7x + 2y = 17 -------> equation 2.

From equation 1,

y = 10 - 4x ------> equation 3.

Substitute equation 3 in 2,

7x + 2 ( 10 - 4x ) = 17

7x + 20 - 8x = 17

7x - 8x = 17 - 20

- x = - 3

x = 3

Substitute x = 3 in equation 1,

4 ( 3 ) + y = 10

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x = 3

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6 0
2 years ago
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If you roll two number cubes ,what is the probability of their sum being 9 or higher?
bija089 [108]

Answer:

5/18

Step-by-step explanation:

When two cubes are rolled there are 36 possibilities

Each dice has 6 equally like outcomes so possibilities are

(1,1)  (1,2)          (1,3)          (1,4)         (1,5)         (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

Now we look at the pair that has sum equal to 9

(3,6) (4,5) (5,4) (6,3) that has sum of 9

Probability of sum is 9 = \frac{4}{36}

we look at the pairs that has sum greater than 9

(4,6) (5,5)(5,6) (6,4)(6,5)(6,6)

Probability of sum greater than 9 = \frac{6}{36}

Probability of sum 9 or higher = P(sum 9) + P(greater than 9)

= \frac{4}{36}+\frac{6}{36}= \frac{10}{36}=\frac{5}{18}



4 0
3 years ago
How do I solve N(1/5) = 2/15
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N(1/5) = (2/15)
divide both sides by (1/5)
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n = 10/15 = 2/3 or 0.666666.
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