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ankoles [38]
2 years ago
12

Sketch two amino acids side by side

Chemistry
1 answer:
alexdok [17]2 years ago
5 0

The sketch of two amino acid side by side is given above.

<h3>What is amino acid? </h3>

Amino acid is defined as the acid which contains two functional groups which are carboxylic group, -COOH and ammine group, -NH2.

When the two or more than two molecules of amino acids join together by forming peptide bond, they produces polypeptide chain or protein.

<h3>What is peptide bond? </h3>

The bond which is present inbetween two amino acid is called a peptide bond.

The peptide bond is defined as a chemical bond which is formed inbetween the two or more molecules when nitrogen which is present in one amino acid react with the carbon of another amino acid by releasing a molecules of water.

Thus we concluded that the two amino acid bond by forming peptide bond.

learn more about amino acid or peptide bond :

brainly.com/question/11559138

#SPJ1

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How many moles are in 29.8grams of CaCl2?
lora16 [44]

Answer:

110.984  ?

i apologize if i'm wrong, you can report it if im wrong

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Explanation:

4 0
3 years ago
I need help with organic chemistry!!!
nadya68 [22]

Answer:

CHO2- ion

Explanation:

We have the lewis structure of a formate-ion here

This is CHO2-.

The carbon atom is the central atom in the structure. It's the least electronegative atom (C). Carbon has 4 valence electrons. Oxygen has 6 valence electrons.

The carbon will bind with 1 hydrogen atom, this will form 1 single bond, because hydrogen has 1 valence electron.

The carbon will bind with oxygen via a double bond.

Since carbon has only 4 valence electrons, it can only form 1 bond with the other oxygen atom.

There will formed 1 double bond between C and O and 1 single bond between C and O resulting in a negative charged O-atom.

This means there are two resonance structures. for the CHO2-  ion

7 0
3 years ago
Units used in gas for pressure
Naya [18.7K]

Answer:

kilopascal, torr, and atmosphere

Explanation:

7 0
3 years ago
011 1.0 points What energy change is associated with the reaction to obtain one mole of H2 from one wang (ew22622) – 19D Thermod
vlada-n [284]

Answer:

<em>249 kJ</em>

Explanation:

To obtain the energy change of the reaction:

H₂O → H₂ + ¹/₂ O₂

It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:

Energy of products:

1 mol of H-H bond × 436 kJ/mol = 436 kJ

¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ

Energy of reactant:

2 mol of H-O bond × 467 kJ/mol = 934 kJ

Energy change of the reaction is:

934 kJ - (436 kJ + 249 kJ) = <em>249 kJ</em>

<em></em>

I hope it helps!

4 0
3 years ago
In the gas-phase reaction 2A + B &lt;-&gt; 3C + 2D, it was found that, when 1.00 mol A, 2.00 mol B, and 1.00 mol D were mixed an
Dvinal [7]

Answer:

Mole fraction: A =  8.70%, B = 37.00%, C =  19.60%, D = 34.80%

K = 6.86

Standard reaction free energy change: -4.77 kJ/mol

Explanation:

Let's do an equilibrium chart for the reaction:

2A + B ⇄ 3C + 2D

1.00  2.00  0     1.00    Initial

-2x     -x     +3x   +2x    Reacts (stoichiometry is 2:1:3:2)

1-2x    2-x    3x    1+2x  Equilibrium

3x = 0.9

x = 0.3 mol

Thus, the number of moles of each one at the equilibrium is:

A = 1 - 2*0.3 = 0.4 mol

B = 2 - 0.3 = 1.7 mol

C = 0.9 mol

D = 1 + 2*0.3 = 1.6 mol

The molar fraction is the mol of the component divided by the total number of moles (0.4 + 1.7 + 0.9 + 1.6 = 4.6 mol):

A = 0.4/4.6 = 0.087 = 8.70%

B = 1.7/4.6 = 0.37 = 37.00%

C = 0.9/4.6 = 0.196 = 19.60%

D = 1.6/4.6 = 0.348 = 34.80%

The equilibrium constant is the multiplication of the concentration of the products elevated by their coefficients, divided by the multiplication of the concentration of the reactants elevated by their coefficients. Because the volume remains constant, we can use the number of moles:

K = (nC³*nD²)/(nA²*nB)

K = (0.9³ * 1.6²)/(0.4² * 1.7)

K = 6.86

The standard reaction free energy change can be calculated by:

ΔG° = -RTlnK

Where R is the gas constant (8.314 J/mol.K), and T is the temperature (25°C = 298 K)

ΔG° = -8.314*298*ln6.86

ΔG° = -4772.8 J/mol

ΔG° = -4.77 kJ/mol

5 0
4 years ago
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