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Greeley [361]
2 years ago
11

The atomic mass of a carbon atom is 12. 011 u. convert this mass to units of kilograms and mev/c2.

Chemistry
1 answer:
timama [110]2 years ago
6 0

The atomic mass of a carbon atom is 12. 011 u. convert this mass to units of kilograms and MeV are 12.011 × 10^(-3) kg and 11182.24MeV.

<h2>What is atomic mass? </h2>

The mass of an atom of a chemical element which is expressed in atomic mass units is termed as atomic mass.

Given,

the atomic mass of carbon atom = 12.011u

As we know that

1u = 1g

12.011u = 12.011g

So. the atomic mass of carbon atom in g = 12.011g

<h3>Atomic mass in Kg</h3>

1 Kg = 1000g

1g = 10^(-3)Kg

12.011g = 12.011 × 10^(-3) kg.

<h3>Atomic mass in MeV</h3>

1u = 931MeV

12.011u = 12.011 × 931MeV

= 11182.24MeV

Thus, the value of atomic mass of carbon atom in Kg and MeV are 12.011 × 10^(-3) kg and 11182.24MeV.

learn more about atomic mass:

brainly.com/question/14250653

#SPJ4

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Pyridine, C5H5N, is a polar organic solvent. How many carbon atoms are in 7.05 moles of pyridine? 4.24 x 1024 4.24 x 10, 24 2.12
leonid [27]

Answer:

2.122×10^25atoms

Explanation:

number of moles=mass/molar mass

7.05moles= mass of pyridine/79

reacting mass of pyridine=556.95

C5H5N= (12×5)+(5)+(14)=79

C5=60

to find the mass of carbon in 556.95g of pyridine we take the stoichometric ratio

60[C5] -----> 79[C5H5N]

x[C5] --------> 556.95g[C5H5N]

cross multiply

x=(60×556.95)/79

x=423g of carbon

moles=mass/molar mass

moles of carbon=423/12

moles=35.25moles of carbon

moles=number of particles/Avogadro's constant

35.25=number of particles/6.02×10^23

number of particles=2.122×10^25atoms of carbon

3 0
3 years ago
Help needed ASAP, I will mark your answer as brainliest.
evablogger [386]

Answer:

b

Explanation:

b

4 0
3 years ago
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In which state(s) of matter are the<br> particles free to move at Gut relative to<br> one another?
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The answer is gas only.
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3 years ago
Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfu
erica [24]

Answer:

194.6 mL of SO₂

Explanation:

The reaction that takes place is:

P₄S₃ + 6O₂(g) → P₄O₁₀ + 3SO₂(g)

<u>To solve this problem we need to use PV=nRT</u>, so first let's convert the given units:

  • 23.8 °C → 23.8 + 273.15 = 296.95 K
  • 747 torr → 747/760 = 0.983 atm

We need to calculate V, so in order to do that we calculate n, using the mass of the reactant (P₄S₃):

0.576 g P₄S₃ * \frac{1molP_{4}S_{3}}{220gP_{4}S_{3}} *\frac{3molSO_{2}}{1molP_{4}S_{3}} = 7.85 * 10⁻³ mol SO₂ = n

  • Now we calculate V:

PV=nRT

0.983 atm * V =  7.85 * 10⁻³ mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.95 K

V = 0.1946 L

  • Finally we convert L into mL:

0.1946 * 1000 = 194.6 mL

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Answer:

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