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3 years ago

Write the equation of the circle with a center at (11,6) and a radius of 6.

Mathematics

2 answers:

AysviL [449]3 years ago

6 0

Answer:

(x - 11)² + (y - 6)² = 36

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (11, 6 ) and r = 6, then

(x - 11)² + (y - 6)² = 6² , that is

(x - 11)² + (y - 6)² = 36

andrew11 [14]3 years ago

3 0

Answer:

(x-11)^2 + (y-6)^2= 6^2

Step-by-step explanation:

You might be interested in

If r = 4 and a6 = 192, what is the first term of the sequence?

blagie [28]

Answer:

Answer: Option c. 0.1875 is the first term of the sequence.

Step-by-step explanation:

In this question sixth term of a sequence is given as A(6)= 192

Ratio of terms is given as 4

And we have to calculate the first term of the sequence.

As per formula A(n) = A(1)× $r^{n-1}$

A(6) = $A(1)(r)^{6-1}$

192 = $A(1)4^{5}$

A(1) = $\frac{192}{4^{5} }$

= 192/1024

=0.1875

So the first term of the sequence will be 0.1875

5 0

3 years ago

Mrs. Lenz rented a scooter during her beach vacation. The cost of the scooter rental is shown for different periods of time. Wha

iragen [17]

Answer:

The unit rate of $10 per hour.

Step-by-step explanation:

Given

$x = time$

$y = amount$

$(x,y) = (1,10)$

See attachment for graph

Required

What does the given point represents

From the attachment, the origin of the graph is:

$(x_1,y_1) = (0,0)$

and we have the given point to be:

$(x_2,y_2) = (1,10)$

Calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{10-0}{1-0}$

$m = \frac{10}{1}$

$m = 10$

The slope represents $10/1 hour

Hence:

$(x,y) = (1,10)$ means the unit rate is $10 per hour

8 0

3 years ago

What is the equivalent exxpression of 8b+8-4b-3

sergiy2304 [10]

8b + 8 - 4b - 3

Combine like terms:-

(8-4)b + 8 - 3
4b + 8 - 3
4b + 5

4 0

3 years ago

Consider the two triangles.

GuDViN [60]

Answer:

(A)Show that the ratios StartFraction U V Over X Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over Z Y EndFraction are equivalent.

$\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}$

Step-by-step explanation:

In Triangles WUV and XZY:

$\angle VUW$ and \angle YXZ$ are congruent. \\\angle U W V$ and \angle X Z Y$ are congruent.\\ \angle U V W$ and \angle Z Y X$ are congruent.$

Therefore:

$\triangle UWV \cong \triangle XZY$

To show that the triangles are similar by the SSS similarity theorem, we have:

$\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}$

As a check:

$\dfrac{UW}{XZ}=\dfrac{40}{32}=1.25\\\\\dfrac{WV}{ZY}=\dfrac{60}{48}=1.25\\\\\dfrac{UV}{XY}=\dfrac{50}{40}=1.25$

The correct option is A.

4 0

3 years ago

Complete the square on the following quadratic x2+10x+9=0

kakasveta [241]

Given a quadratic equation $x^{2} +ax+c=0$

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + $5^{2}$ and - $5^{2}$ to the expression:

$x^{2} +2*5*x+ 5^{2} -5^{2}+9=0$

$(x^{2} +2*5*x+ 5^{2}) -25+9=0$

$(x+5)^{2}-16=0$

Answer: $(x+5)^{2}-16=0$

8 0

3 years ago