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Elan Coil [88]
3 years ago
15

Write the equation of the circle with a center at (11,6) and a radius of 6.

Mathematics
2 answers:
AysviL [449]3 years ago
6 0

Answer:

(x - 11)² + (y - 6)² = 36

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (11, 6 ) and r = 6, then

(x - 11)² + (y - 6)² = 6² , that is

(x - 11)² + (y - 6)² = 36

andrew11 [14]3 years ago
3 0

Answer:

(x-11)^2 + (y-6)^2= 6^2

Step-by-step explanation:

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A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
The midpoint of is point P at (−16,6). If point A is at (−10,8), what are the coordinates of point B? (−42,20) (−22,4) (−13,7) (
statuscvo [17]

Answer:

B (-22 ,  4)

Step-by-step explanation:

-16=(-10+x)/2

*2      *2

-10+x=-32

+10       +10

x=-22

6=(8+y)/2

*2      *2

12=8+y

-8    -8

4=y

so B(-22,  4)

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If they intersect eachother then the answer is true
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