Answer:
About 175.47
Step-by-step explanation:
*The answer is decimal*
.53*x=93
93/.53= about 175.47
Answer: 12650
Step-by-step explanation:
It can be done in C25 4 = 25!/(25-4)!/4!= 25!/21!/(2*3*4)=
=22*23*24*25/24=22*23*25= 12650 variants
Question:
Which is equivalent to
after it has been simplified completely?
Answer:

Step-by-step explanation:
Given

Required
Simplify
We start by splitting the square root

Replace 180 with 36 * 5

Further split the square roots


Replace power of x; 11 with 10 + 1

From laws of indices; 
So, we have


Further split the square roots

From laws of indices; 
So, we have



Rearrange Expression


From laws of indices; 
So, we have



<em>The expression can no longer be simplified</em>
Hence,
is equivalent to 
Answer:
40 girls
Step-by-step explanation:
Set up a proportion where x is the number of girls in band class:
= 
Cross multiply and solve for x:
3x = 120
x = 40
So, there were 40 girls in band class.
Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92
The 90th percentile score is nothing but the x value for which area below x is 90%.
To find 90th percentile we will find find z score such that probability below z is 0.9
P(Z <z) = 0.9
Using excel function to find z score corresponding to probability 0.9 is
z = NORM.S.INV(0.9) = 1.28
z =1.28
Now convert z score into x value using the formula
x = z *σ + μ
x = 1.28 * 92 + 1028
x = 1145.76
The 90th percentile score value is 1145.76
The probability that randomly selected score exceeds 1200 is
P(X > 1200)
Z score corresponding to x=1200 is
z = 
z = 
z = 1.8695 ~ 1.87
P(Z > 1.87 ) = 1 - P(Z < 1.87)
Using z-score table to find probability z < 1.87
P(Z < 1.87) = 0.9693
P(Z > 1.87) = 1 - 0.9693
P(Z > 1.87) = 0.0307
The probability that a randomly selected score exceeds 1200 is 0.0307