Answer:

Explanation:
F₁ = Force on one side of the jack
A₁ = Area of cross-section of one side of the jack
F₂ = Force on second side of the jack
A₂ = Area of cross-section of second side of the jack = 2 A₁
Using pascal's law




Answer:
The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards
Explanation:
Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.
Therefore since we can use 3,056 yards of fencing
Side perpendicular to the river = x and,
Side opposite to the river = y = 3056 - 2x
The area of the rectangle formed (A) = Perpendicular side × Parallel side
∴ A = x(3056 - 2x) = 3056x - 2x²
A = 3056x - 2x²
To maximize the area, A' (dA/dx) = 0
∴ A' = 3056 - 4x = 0
3056 - 4x = 0
4x = 3056
x = 764 yards
y = 3056 - 2x = 3056 - 2(764) = 1528 yards.
Side perpendicular to the river = 764 yards and,
Side opposite to the river = 1528 yards
The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards
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Answer:
e^-4t e^-5t
Explanation:
solving s²+9s+20 quadratically we have (s+4)(s+5)
x(s) can be written as x(s) =(1/s+4)(1/s+5)
if we take the laplace inversve
L-¹ (s)=L-1(1/s+4) L-1(1/s+5)
we have e^-4t e^-5t