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babunello [35]
3 years ago
7

If you are looking for a substance that will easily dissolve in water, you should look for a substance with which properties?

Physics
1 answer:
olga nikolaevna [1]3 years ago
5 0
<span>If you are looking for a substance that will easily dissolve in water, you should look for a substance with which properties? it is b. high solubility

</span>
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A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.
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Answer:

Approximately 13\; {\rm N \cdot m^{-1}} (assuming that g = 9.81\; {\rm N \cdot kg^{-1}}.)

Explanation:

Let F_{\text{s}} denote the force that this spring exerts on the object. Let x denote the displacement of this spring from the equilibrium position.

By Hooke's Law, the spring constant k of this spring would ensure that F_\text{s} = -k\, x.

Note that the mass of the object attached to this spring is m = 540\; {\rm g} = 0.540\; {\rm kg}. Thus, the weight of this object would be m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}.

Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, F_{\text{s}} = 5.230\; {\rm N}.

The spring in this question was stretched downward from its equilibrium by:

\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}.

(Note that x is negative since this displacement points downwards.)

Rearrange Hooke's Law to find k in terms of F_{\text{s}} and x:

\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}.

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What is the amount of thermal energy needed to raise the temperature of 1 of a substance by ?
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Answer:

It is the amount of energy required to raise the temperature of one gram of a substance by one degree Celsius.

Explanation:

Hope this helps and have a good day

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Without friction, the car cannot stop...

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A student performed the following steps to find the solution to the equation x^2-2x-15=0 Where did the student go wrong? STEP 1:
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B. In step 3

They incorrectly solved for x. It should have been x=-3 and x=5
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