Answer:
Yes Kevin is correct
Step-by-step explanation:
The index, x, of a radical ˣ√ is the numerical value of the root sought of the number located under (within) the radical sign
Therefore, when the index is even, we have, numbers for the radical given by 2x, therefore we have;
⁽²ˣ⁾√(a²ˣ)
Where a = The 2x root of the radicand
Therefore, we can write, a²ˣ = aˣ × aˣ
For which aˣ can be neqative but will still give a positive value
Therefore, when the index is even, the roots can either be a positive or a negative real number, which are two real numbers, +a or -a
![\sqrt[2\cdot x]{a^{2\cdot x}} = \left | a \right | = \pm a](https://tex.z-dn.net/?f=%5Csqrt%5B2%5Ccdot%20x%5D%7Ba%5E%7B2%5Ccdot%20x%7D%7D%20%20%3D%20%5Cleft%20%7C%20a%20%5Cright%20%7C%20%3D%20%5Cpm%20a)
$3.75
Step-by-step explanation:
times 3.25 by 5 which is 16.25 then do 20 - 16.25
2.5 x 10⁻²
Move the decimal two places to the right and multiply by 10 to the power of -2
◆ COMPLEX NUMBERS ◆
125 ( cos 288 + i sin 288 ) can be written as -
125.e^i( 288)
125.e^i( 288 +360 )
125.e^i( 288+ 720)
[ As , multiples of 360 can be added to an angle without changing any trigonometric functions or sign ]
To find the cube root , take the cube root of above 3 expressions ,
We get -
5 e^( i 96 )
5 e^( i 216 )
5 e^( i 336 )
Now using Euler's formula , We rewrite above as -
5 ( cos 96 + i sin 96 )
5(c os 216 + i sin 216 )
5 ( cos 336 + i sin 336 ) Ans.
