Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:
Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
12a−a
=12a−1a
=12a+−1a
=a+a+a+a+a+a+a+a+a+a+a+a+−a
=a+a+a+a+a+a+a+a+a+a+a
=11a
To solve this problem you must apply the proccedure shown below:
1. You have that the time, given in the problem above, is written in decimal form.
2. To express this time in words, you must begin from left to right. First, write the digits before the point (58) and after the points (329) as whole numbers. Then, finish it writting the place name of the last digit, as following:
(Note: The point is expressed as "and").
58.329: Fifty eigth and three hundred twenty nine thousandths.
Therefore, the answer is: Fifty eigth and three hundred twenty nine thousandths.
C because people wasn’t allowed to get a lot of the things they wanted
5 has the value of thousandths place
