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frozen [14]
3 years ago
8

What is ​ 2410 ​ expressed as a decimal? Enter your answer in the box.

Mathematics
2 answers:
Allisa [31]3 years ago
7 0
It cannot be expressed as a decimal because it is a whole number but it could be written like this, 2410.0
tia_tia [17]3 years ago
3 0
Ummm... 2410.00? the\is isnt a fracion or a percent soooo it cant be a decimal. lol BUT if youre talking about binary code then maybe i can help :)

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Find the value of (2^−2 − 4^0) × 4^−2​
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-0,046875

Step-by-step explanation:

( {2}^{ - 2}  -  {4}^{0} ) \times  {4}^{ - 2}  \\  = (0.25 - 1) \times 0.0625 \\  =  - 0.75 \times  0.0625 \\  =  - 0.046875

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A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
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Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

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