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2 years ago

PLEASE HELP 20!!+BRAINLIEST

1 answer:

6 0

It is important to be able to describe a system quantitatively because there exist many variables that show a continuous range of variation.

<h3>What is quantitative research?</h3>

Quantitative research is any type of investigation based on scientific variables that express their values as a continuous range of variation.

For example, there are genetic traits such as height and weight that show quantitative variation, thereby they need to be expressed as ranges.

In conclusion, it is important to be able to describe a system quantitatively because there exist many variables that show a continuous range of variation.

Learn more about quantitative research here:

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We now slowly increase the pressure to 15464.04 Pa while keeping the temperature constant. What is the final volume?

Mila [183]

Answer:

Final volume = 0.42 cubic meters

Explanation:

The question is incomplete. The initial conditions are

Initial temperature , $T_{1}$ = 310 K

Initial volume , $V_{1}$ = 0.5 cubic meter

Number of moles = 2.5

Since, from the ideal gas equation we get,

PV = nRT

P $\times 0.5 = 2.5 \times 8.314 \times 310$

$P_{1}$ = 12886.7 Pa

Final pressure= 15464.04 Pa

Since temperature is constant,

PV = constant

$12886.7 \times 0.5 = 15464.04 \times V$

V = 0.42 cubic meters.

Hence final volume = 0.42 cubic meters

8 0

3 years ago

A long straight wire carries a 40.0 A current in the +x direction. At a particular instant, an electron moving at 1.0  107 m/s

ser-zykov [4K]

Answer:

$F=-1.28\times 10^{-16}\ N$

Explanation:

Given that,

Current flowing in the wire, I = 40 A (+x direction)

Speed of the electron, $v=10^7\ m/s$ (+y direction)

Distance from the wire, r = 0.1 m

Let F is the electric force on the electron. It is given by :

$F=qvB\ sin\theta$

Here, $\theta=90$

$F=qvB$

Here, $B=\dfrac{\mu_oI}{2\pi r}$

$F=qv\dfrac{\mu_oI}{2\pi r}$

$F=-1.6\times 10^{-19}\times 10^7\times \dfrac{4\pi\times 10^{-7}\times 40}{2\pi \times 0.1}$

$F=-1.28\times 10^{-16}\ N$

So, the force on the electron at this instant is $-1.28\times 10^{-16}\ N$ . Hence, this is the required solution.

5 0

4 years ago

you have a 200 kg bag being lifted with a block and tackle. If you pull with 100 newtons what is the MA of the system?

Korvikt [17]

Answer:

The mechanical advantage of the system is equal to 19.62

Explanation:

The ratio of the force produced by a machine to the force applied to it is called mechanical advantage. In other words it is the ratio of output force to the input force.

In this problem mass=200kg

applied force=100N

input force=100N

output force= $mg=200 \times 9.8=196N.$

mechanical advantage $MA= \frac{1960}{100}=19.6$

It gives an idea about the efficiency of a mechanical device. It is indeed a measure of force amplification. In block and tackle system an assembly of ropes and pulleys is used to lift loads. When the moving block is supported by a greater number of rope sections the force amplification will be more.

7 0

3 years ago

Read 2 more answers

A plane circular loop of conducting wire of radius with possesses turn is placed in a uniform magnetic field. The direction of t

amid [387]

Complete question;

A plane circular loop of conducting wire of radius r-10 cm which possesses 15 turns is placed in a uniform magnetic field. The direction of the magnetic field makes an angle of 30° with respect to the normal direction to the loop. The magnetic field-strength is increased at a constant rate from IT to 5T in a time interval of 10 s.

a) What is the emf generated around the loop?

b) If the electrical resistance of the loop is 15Ω, what current flows around the loop as the magnetic field is increased?

Answer:

A) E.M.F generated around loop = 0.1632 Wb/s

B)Current in loop; I = 0.0109 A

Explanation:

A) We are given;

Initial magnetic field strength;B1 = 1T

Final magnetic field strength;B2 = 5T

Number of turns;N = 15 turns

Radius; r = 10cm = 0.1m

Angle;θ = 30°

Time interval; Δt = 10 s

Now, the formula for magnetic flux is: Φ = NABcosθ

Where;

N is number of turns

A is area = πr²

B is magnetic field strength

θ is angle

So, initial magnetic flux is;

Φ1 = NA(B1)cosθ

Plugging in the relevant values to obtain;

Φ1 = 15*(π*0.1²)(1)cos30

Φ1 = 0.4081 Wb

Similarly, final magnetic flux is;

Φ2 = NA(B2)cosθ

Plugging in the relevant values to obtain;

Φ2 = 15*(π*0.1²)(5)cos30

Φ2 = 2.0405 Wb

The time rate of change of the flux is;

dΦ_B/dt = (Φ2 - Φ1)/Δt

So, dΦ_B/dt = (2.0405 - 0.4081)/10

dΦ_B/dt = 0.1632 Wb/s

Thus, the emf generated around the loop is; E = dΦ_B/dt = 0.1632 Wb/s

B) from Ohm's law, the current which flows around the loop in response to the emf is given as;

I = E/R

We are given R =15Ω

Thus; I = 0.1632/15

I = 0.0109 A

θπΦ

4 0

3 years ago

Adhesion is when forces of the molecules are more strongly drawn to each other than the molecules in other substances true or fa

SSSSS [86.1K]

Answer:

False

Explanation:

that is cohesion. adhesion is force between dissimilar molecules of a body

6 0

4 years ago