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3 years ago

8.)The potential energy of a 40-kg cannonball is 14000 J. How high was the cannon ball to have this much potential energy?

Physics

1 answer:

Delvig [45]3 years ago

7 0

Hey! I empathize with you, as I just started the energy unit in physics as well!

Alright, lets list what we know, and which equation(s) we need.

PE = Gravitational Potential Energy

$PEg = mgh$

m = mass

g = gravity (9.8 m/s^2)

h = height

Guess what?

We need to find the height!

Lets make this more organized:

Known:

m = 40 kg

PE = 14000

g = 9.8 m/s^2

Unknown:

h = ?

================================

Now, if we take a look at the equation PEg = mgh, you will see that we have everything besides the height! So lets solve for the height by substituting in for the variables we know:

14000 J = 40 kg * (9.8 m/s^2) * h

40 * 9.8 = 392

14000 J = 392 * h

14000/392 = h

35.71 m = h

There we go! If you simply list what you know and don't know, you will find the equation you need to solve the problem.

Have a great day and good luck!

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3 years ago

The heat capacity of 0.125Kg of water is measured to be 523j/k at a room temperature.Hence, calculate the heat capacity of water

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Answer:

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B. 4148 J/K/L

Explanation:

A. Heat capacity per unit mass is known as the specific heat capacity, c.

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C = (523 J/K) / 0.125 Kg = 4148 J/K/Kg

B. Volume of water = mass/density

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3 years ago

An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers (n = 3.50

sasho [114]

Answer:

d = 6.43 cm

Explanation:

Given:

- Speed resistance coefficient in silicon n = 3.50

- Memory takes processing time t_p = 0.50 ns

- Information is to be obtained within T = 2.0 ns

Find:

- What is the maximum distance the memory unit can be from the central processing unit?

Solution:

- The amount of time taken for information pulse to travel to memory unit:

t_m = T - t_p

t_m = 2.0 - 0.5 = 1.5 ns

- We will use a basic relationship for distance traveled with respect to speed of light and time:

d = V*t_m

- Where speed of light in silicon medium is given by:

V = c / n

- Hence, d = c*t_m / n

-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50

d = 0.129 m 12.9 cm

- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm

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3 years ago

An object completes 2500 cycles in<br> 26s. The radius of motion is 3.5m.

Evgesh-ka [11]

Answer:

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Explanation:

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3 years ago

A piece of wire 25 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

Dmitry [639]

Answer:

10.87 m

Explanation:

Total length of the wire = 25 m

Let the length of one piece is y and other piece is 25 - y

Let the side of square is a.

So, 4 a = y

a = y / 4

And the side of triangle is b

3 b = (25 - y)

b = (25 - y) / 3

Area of square, A1 = side x side =

A1 = y² / 16

Area of equilateral triangle, A2 = $\frac{\sqrt{3}}{4}\times b^{2}$

$A_{2}=\frac{\sqrt{3}}{4}\frac{\left ( 25-y \right )^{2}}{9}$

Total area, A = A1 + A2

$A=\frac{y^{2}}{16}+\frac{\sqrt{3}}{4}\frac{\left ( 25-y \right )^{2}}{9}$

For maxima and minima, fins dA /dy

$\frac{dA}{dy}=\frac{y}{8}-\frac{1.732}{18} \times \frac{25-y}{1}$

It is equal to zero.

$\frac{y}{8}=\frac{1.732}{18} \times \frac{25-y}{1}$

9y = 173.2 -6.928 y

15.928 y = 173.2

y = 10.87 m

So, the length of wire to make square is 10.87 m.

3 0

3 years ago