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Naddik [55]
4 years ago
14

Lab safety is not only important in the classroom, but it is also important to follow

Chemistry
1 answer:
defon4 years ago
4 0

Answer:

Follow safety measures and safety rules to avoid any accident.

Explanation:

1. Follow all safety measures is needed from adults when they conducting any experiment at home in order to prevent any damage occurs due to that experiment.

2. Safety rules should always be followed when conducting an experiment at any place such as at home, class room and laboratory etc in order to avoid any accident.

3. Some chemicals are very dangerous because they are flammable and catch fire when allow it to the heat source. Some chemicals also cause suffocation by absorbing all the oxygen from the environment and as a result death occurs.

4. Science is a systematic study of physical objects through observation and experiments. Science is a knowledge gain from experiments.

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In the experiment, 40 mL of 3 M sodium hydroxide is used to extract the benzoic acid. In order to recover the benzoic acid from
nikdorinn [45]

Answer:

20 mL OF 6 M HYDROCHLORIC ACID WILL BE NEEDED

Explanation:

M1 V1 = M2 V2

M1 = Molarity of sodium hydroxide = 3 M

V1 = volume of sodium hydroxide = 40 mL

M2 = Molarity of hydrochloric acid = 6 M

V2 = Volume of hydrochloric acid = unknown

Rearranging the equation, we have:

V2 = M1 V1 / M2

V2 = 3 * 40 mL / 6

V2 = 120 / 6

V2 = 20 mL

To precipitate the benzoic acid by 6 M of hydrochloric acid, 20 mL volume will be needed.

6 0
3 years ago
What's similar about the valence electrons of Carbon and Silicon?
Mars2501 [29]

Answer:

Explanation: Carbon and silicon BOTH come from Group 14 of the Periodic Table , i.e. both formally have the same number of valence electrons, 4 such electrons.........

5 0
2 years ago
When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t
satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

Explanation:

Heat lost by solution ad calorimeter = Q

Heat capacity of solution ad calorimeter = C = 1071 J/°C

Change in temperature = ΔT = 21.56°C - 25.00°C = -3.44°C

Q=C\times Delta T

Q=1071 J/^oC\times (-3.44^oC)=-3,684.24 J

Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

Moles of sodium nitrate = \frac{15.3 g}{85 g/mol}=0.18 mol

When 0.18 mole of sodium nitrate was dissolved in water 3,684.24 joulesof heat was absorbed by it.

Then heat absorbed by 1 mole of sodium nitrate :

\frac{3,684.24 J}{0.18}=20,468 J=20.468 kJ

1 J = 0.001 kJ

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

8 0
3 years ago
Hi! please help me identify the IUPAC name for the structures ​
Snowcat [4.5K]

The IUPAC names of the organic compounds would be as follows:

1. Methanol or 1-Methanol

2. Propan-2-ol or 2-Propanol

3. 2-MethylButane

4. 1-Hexanol

5. 1-Heptanol

<h3>Naming organic compounds</h3>

In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:

  • The longest carbon chain, otherwise known as the parent chain, is considered.
  • The substituents must be identified
  • The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
  • Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.

Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:

  • Methanol or 1-Methanol
  • Propan-2-ol or 2-Propanol
  • 2-MethylButane
  • 1-Hexanol
  • 1-Heptanol

More on IUPAC naming can be found here: brainly.com/question/16631447

#SPJ1

7 0
1 year ago
Determine the maximum number of moles of product that can be produced from 7.0 mol al and 8.0 mol cl2 according to the equation
Vilka [71]
The balanced chemical reaction is

<span>2al + 3cl2 = 2alcl3

To determine the maximum amount of product, we need to determine which is the limiting reactant. Then, use the initial amount of that reactant to calculate the amount of the product that would be produced. We do as follows:

7 mol Al (3 mol Cl2 / 2 mol Al) = 10.5 mol Cl2
8 mol Cl2 ( 2 mol Al / 3 mol Cl2) = 5.3 mol Al
Thus, it is Cl2 that is the limiting reactant.

8 mol Cl2 ( 2 mol AlCl3 / 3 mol Cl2) = 5.3 moles of AlCl3 is produced</span>
5 0
4 years ago
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