0.375 L of the NaCl solution contains 0.455 moles (1)
since it was diluted to 1.88 L
then let 1.88 L of solution contain x moles (2)
by combining both (1) and (2)
⇒ (0.345 L) x = (0.455 mol) (1.88 L)
⇒ x = (0.242 mol · L) ÷ (0.345 L)
⇒ x = 0.702 mol
Thus the molarity of the NaCl after being diluted is 0.702 M OR 0.702 mol / L OR 0.702 mol/dm³.
Answer:
The value is 
Explanation:
From the question we are told that
The equation is 
The temperature is ![T = 25^oC = 298 K [room \ temperature ]](https://tex.z-dn.net/?f=%20T%20%3D%2025%5EoC%20%3D%20%20298%20K%20%20%20%5Broom%20%20%5C%20temperature%20%5D)
The emf at standard condition is 
Generally at the cathode

At the anode

Generally for an electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as

Here n is the no of electron with value n = 6
F is the Faraday's constant with value 96487 J/V
=>
=> 
This Gibbs free energy can also be represented mathematically as

Here R is the cell constant with value 8.314J/K
K is the equilibrium constant
From above
=> 
Generally antilog = 2.718
=>
=> 
Answer:
A physical property that depends on the sample size
Explanation:
Answer: This image is the answer to this question.
Explanation: