M(C)=73.5 g
m(H)=4.20 g
m(Cl)=72.3 g
mass of compound
m=m(C)+m(H)+m(Cl)
m=73.5+4.20+72.3=150 g
w(H)=100m(H)/m
w(H)=100*4.20/150=2.8%
w(Cl)=100m(Cl)/m
w(Cl)=100*72.3/150=48.2%
w(C)=100-w(H)-w(Cl)
w(C)=100-2.8-48.2=49.0%
Answer:
The frog has 4 toes on each foot in the front, and 5 toes on each foot in the back.
Explanation:
The answer to the question is B......
Answer:
Mass of sodium chloride decomposed = 24.54 g
Explanation:
Given data:
Mass of sodium chloride decomposed = ?
Mass of chlorine gas formed = 15 g
Solution:
Chemical equation:
2NaCl → 2Na + Cl₂
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 15 g/ 71 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Cl₂ with NaCl from balance chemical equation.
Cl₂ : NaCl
1 : 2
0.21 : 2×0.21 = 0.42 mol
Mass of Sodium chloride decompose:
Mass = number of moles × molar mass
Mass = 0.42 mol × 58.44 g/mol
Mass = 24.54 g
