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Brut [27]
3 years ago
15

The main product of the photosynthesis reaction is

Chemistry
1 answer:
Paladinen [302]3 years ago
4 0

Answer: Sugar

Explanation: Because after photosynthesis (Carbon dioxide, water, and sunlight) react, they make two products. Glucose (A sugar) and Oxygen.

You might be interested in
How do you balance the equation in number one?
AleksAgata [21]
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O

To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side. 

To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

[reactants]        [product]
Na- 1               Na- 2

N- 1               N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)

O- 4              O- 7 (same reason as above) 

Pb- 1            Pb- 1 

Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2: 

2NaNO3

Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become: 

Na- 2             Na- 2 

N- 2              N- 2 (it balanced out) 

O- 7 (coefficient times subscript, plus lone O)  O- 7 (balanced out) 

Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything). 

Now to put it back together, it will look like this: 

2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
3 0
3 years ago
Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
sergiy2304 [10]
The balanced chemical reaction is:

<span>3N2H4(l)→4NH3(g)+N2(g)
</span>
The amounts given for the N2H4 reactant will be the starting point for our calculations.

2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3

4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

63.8g N2H4  <span>( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3</span>
7 0
4 years ago
Consider the synthesis of ammonia 3 H2+ N2 à 2 NH3 If a student were to react 38.5 g of nitrogen gas, how many moles of ammonia
Wittaler [7]

Answer:

2.75 mol

Explanation:

Given data:

Mass of Nitrogen = 38.5 g

Moles of ammonia produced = ?

Solution:

Chemical  equation:

N₂ + 3H₂    →     2NH₃

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 38.5 g/ 28 g/mol

Number of moles = 1.375 mol

Now we will compare the moles of ammonia and nitrogen from balance chemical equation.

           N₂            :            NH₃

            1              :             2

           1.375       :           2×1.375 = 2.75 mol

Thus 2.75 moles of ammonia  are produced from 38.5 g of nitrogen.

4 0
3 years ago
What could be the fourth quantum number of a 1s^2 electron be?
Bumek [7]

The forth quantum number is Spin quantum number and the value of Spin Quantum Number of 1s² will be +1/2. Therefore, the correct option is (B) option

<h3>What is Spin Quantum Number ?</h3>

It describes the orientation of the electron spin (rotation) in space.

In the given case of 1s² configuration,

since, the Quantum numbers are known as:

  • Principal quantum number (n) which cannot be zero.

       The allowed values of n are therefore 1, 2, 3, 4, and so on.

  • Angular quantum number (l) is able to be any integer between 0  

       and n-1.

       Therefore, for example, If n = 1, l will be 0,

                                                If n = 2, l can be either 0 or 1.

  • Magnetic quantum number (m) is able to be any integer between -l and +l.    

       Therefore, for example, If l = 3, m can be either -3 to +3.

  • Spin Quantum Number (ms): Ms = +½ or -½  accounts for the orientation of the spin axis of an electron as it is able to spin in only one of two directions.

Thus, since the fourth quantum number is Ms, spin, we infer that the answer is (B) option ie, Ms = +1/2 because it represents the positive spin on 1s².

Learn more about Quantum Number Here ;

brainly.com/question/15325270

#SPJ1

6 0
2 years ago
"determine the mass of oxygen" in a 7.9 g sample of al2(so4)3.
jeyben [28]

Answer:

              4.43 g of Oxygen

Explanation:

As shown in Chemical Formula, one mole of Aluminium Sulfate [Al₂(SO₄)₃] contains;

                          2 Moles of Aluminium

                          3 Moles of Sulfur

                          12 Moles of Oxygen

Also, the Molar Mass of Aluminium Sulfate is 342.15 g/mol. It means,

          342.15 g ( 1 mole) of Al₂(SO₄)₃ contains  =  192 g (12 mole) of O

So,

                         7.9 g of Al₂(SO₄)₃ will contain  =  X g of O

Solving for X,

                       X  =  (7.9 g × 192 g) ÷ 342.15 g

                      X =  4.43 g of Oxygen

7 0
3 years ago
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