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irga5000 [103]
1 year ago
9

Hi! please help me identify the IUPAC name for the structures ​

Chemistry
1 answer:
Snowcat [4.5K]1 year ago
7 0

The IUPAC names of the organic compounds would be as follows:

1. Methanol or 1-Methanol

2. Propan-2-ol or 2-Propanol

3. 2-MethylButane

4. 1-Hexanol

5. 1-Heptanol

<h3>Naming organic compounds</h3>

In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:

  • The longest carbon chain, otherwise known as the parent chain, is considered.
  • The substituents must be identified
  • The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
  • Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.

Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:

  • Methanol or 1-Methanol
  • Propan-2-ol or 2-Propanol
  • 2-MethylButane
  • 1-Hexanol
  • 1-Heptanol

More on IUPAC naming can be found here: brainly.com/question/16631447

#SPJ1

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The disturbance of a supersaturated solution will cause
Flura [38]
The disturbance of a supersaturated solution will cause precipitation. A supersaturated solution is a solution that contains more solute than the solvent can dissolve. When this type of solution is disturbed like when it is moved, the formation of a solid is observed immediately.
3 0
3 years ago
When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. What element is formed?
Galina-37 [17]

That will make a gold-202 nucleus.

<h3>Explanation</h3>

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the \displaystyle ^{202}_{\phantom{2}80}\text{Hg} with a neutron ^{1}_{0}n. The neutron will add 1 to the mass number 202 of ^{202}_{\phantom{2}80}\text{Hg}. However, the atomic number will stay the same.

  • New mass number: 202 + 1 = 203.
  • Atomic number is still 80.

^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}.

Double check the equation:

  • Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
  • Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.

Step Two: The ^{203}_{\phantom{2}80}\text{Hg} nucleus loses a proton ^{1}_{1}p. Both the mass number 203 and the atomic number will decrease by 1.

  • New mass number: 203 - 1 = 202.
  • New atomic number: 80 - 1 = 79.

Refer to a periodic table. What's the element with atomic number 79? Gold Au.

^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p.

Double check the equation:

  • Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
  • Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.

A gold-202 nucleus is formed.

6 0
3 years ago
I am having trouble converting :(
Elza [17]

Answer:

For the first question, to determine the total number of molecules of nitrogen dioxide, first make use of the molar mass of the nonpolar compound and then use that to find the total number of moles and then subsequently after make use of the ratio for the Avogadro's number to determine the total number of molecules of this compound.

For the final question, do the inverse, where we make use of the molecules of the compound and then use Avogadro's number to determine the moles of the compound and then use the same molar mass of the compound to determine the grams of the Nitrogen Dioxide.

3 0
3 years ago
How many moles of CaO are needed to react with excess water to produce 370g of calcium hydroxide?
never [62]

Answer:

5 moles

Explanation:

CaO+H20--> Ca(OH)2

mass 280 90 370g

RFM 56 18 74

moles 5 5 5

4 0
3 years ago
Which of the following are elements in this equation:
Anit [1.1K]

Answer:

calcium they are basically group 1,2,3 elements

4 0
3 years ago
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