Answer:
89.94 %
Explanation:
Considering:
Or,
Given :
For HCl :
Molarity = 0.500 M
Volume = 22.5 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 22.5×10⁻³ L
Thus, moles of HCl :
![Moles=0.500 \times {22.5\times 10^{-3}}\ moles](https://tex.z-dn.net/?f=Moles%3D0.500%20%5Ctimes%20%7B22.5%5Ctimes%2010%5E%7B-3%7D%7D%5C%20moles)
Moles of HCl = 0.01125 moles
The reaction of NaOH and HCl is:
NaOH + HCl ⇒ NaCl + H₂O
Moles of HCl = Moles of NaOH
<u>Thus, Moles of NaOH = 0.01125 moles</u>
Molar mass of NaOH = 39.997 g/mol
The formula for the calculation of moles is shown below:
Thus,
![Mass of NaOH= 0.4497\ g](https://tex.z-dn.net/?f=Mass%20of%20NaOH%3D%200.4497%5C%20g)
Total mass = 0.500 g
<u>% purity = ( 0.4497 / 0.500 ) × 100 = 89.94 %</u>
Answer
Long live Pop smoke
Explanation
Answer:
11.3 g of
are produced from 36.0 g of ![H_{2}O](https://tex.z-dn.net/?f=H_%7B2%7DO)
Explanation:
1. The balanced chemical equation is the following:
![Mg_{3}N_{2}(s)+6H_{2}O(l)=3Mg(OH)_{2}(s)+2NH_{3}(g)](https://tex.z-dn.net/?f=Mg_%7B3%7DN_%7B2%7D%28s%29%2B6H_%7B2%7DO%28l%29%3D3Mg%28OH%29_%7B2%7D%28s%29%2B2NH_%7B3%7D%28g%29)
2. Use the molar mass of the
, the molar mass of the
and the stoichiometry of the balanced chemical reaction to find how many grams of
are produced:
Molar mass
= 18![\frac{g}{mol}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7Bmol%7D)
Molar mass
= 17![\frac{g}{mol}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7Bmol%7D)
![36.0gH_{2}O*\frac{1molH_{2}O}{18gH_{2}O}*\frac{2molesNH_{3}}{6molesH_{2}O}*\frac{17gNH_{3}}{1molNH_{3}}=11.3gNH_{3}](https://tex.z-dn.net/?f=36.0gH_%7B2%7DO%2A%5Cfrac%7B1molH_%7B2%7DO%7D%7B18gH_%7B2%7DO%7D%2A%5Cfrac%7B2molesNH_%7B3%7D%7D%7B6molesH_%7B2%7DO%7D%2A%5Cfrac%7B17gNH_%7B3%7D%7D%7B1molNH_%7B3%7D%7D%3D11.3gNH_%7B3%7D)
Therefore 11.3 g of
are produced from 36.0 g of ![H_{2}O](https://tex.z-dn.net/?f=H_%7B2%7DO)
Explanation:
Molar mass of
= 39.1 + 35.5 + 3(16.0) = 122.6 g
Molar mass of KCl = 39.1 + 35.5 = 74.6 g
Molar mass of
= 32.0 g
According to the equation, 2 moles of
reacts to give 3 moles of oxygen.
Therefore, 2 (122.6) = 245.2 g of
will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of
gives 96.0 g of oxygen.
(a) Calculate the amount of oxygen given by 2.72 g of
as follows.
of
(b) Calculate the amount of oxygen given by 0.361 g of
as follows.
of
c) Calculate the amount of oxygen given by 83.6 kg
as follows.
of ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
Convert kg into grams as follows.
= 32731 g of ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
(d) Calculate the amount of oxygen given by 22.5 mg of
as follows.
![\frac {96g}{245.2g} \times 22.5 mg = 8.79 mg](https://tex.z-dn.net/?f=%5Cfrac%20%7B96g%7D%7B245.2g%7D%20%5Ctimes%2022.5%20mg%20%3D%208.79%20mg)
Convert mg into grams as follows.
of ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
Answer:
FALSE!
Explanation:
It was created millions of years ago.