You can do this by drawing one line through parallel to PQS to meet RQ at T
Now calculate length of RT:-
cos 70 = RT / 70 giving RT = 23.94m
sin 70 = ST/70 giving ST = 65.78 m
draw a line from S perpendicular to PQ to meet PQ at U.
PU = 110 - 65.78 = 44.22 m
tan 50 = SU / 44.22 giving SU = 52.70 m
TQ = SU = 52.70 m
So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.
The first answer is B because the bottom half of the proportions are how many km/minutes he CAN run, while the top half of the proportion is how many he WILL run.
He will run 60km in 285 minutes.
7/22 you add the denominators toghether and add the numerators.
3 / (1/8) = 3 × (8/1) = 24
There needs to be 24 students on a team.
Answer:
4
Step-by-step explanation:
(32 + x)/6=6
