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Naddika [18.5K]

3 years ago

9

For it's checking plus account a bank charges $3.95 per month plus $0.10 for each check written after the first ten checks writt

en for the month. Greg writes 24 checks in March. How much will he pay the bank fees for the month? B,How would you solve this problem explain the step you would take. C, What is one important detail from this problem that you think people might commonly miss?

1 answer:

sp2606 [1]3 years ago

8 0

Answer:

$5.35.

Step-by-step explanation:

The number of checks written after the first 10 = 24 - 10 = 14.

The fees for these checks = 14 * 0.10

= $1.40.

So his fees for March are 3.95 + 1.40

= $5.35.

C. they might miss realising that the first 10 checks are free.

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A print shop borrows $6700 from a credit union for 338 days the credit union charges simple interest at an annual rate of 10% fo

bekas [8.4K]

Answer:

The total he would have to pay back would be $7,320.44

Step-by-step explanation:

(I'm assuming you want the total amount he needs to pay back)

6700 x 0.10 = 670 per year

670 ÷ 365 = 1.835616438356164

1.835616438356164 × 338 = 620.44

620.44 + 6700 = 7,320.44

3 0

2 years ago

The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in

oksano4ka [1.4K]

Answer:

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

$p_v =P(Z>2)=0.0228$

Step-by-step explanation:

1) Data given and notation

$\bar X=8300$ represent the sample mean

$\sigma=1200$ represent the population standard deviation

$n=64$ sample size

$\mu_o =800$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

4) P-value

Since is a one-side upper test the p value would given by:

$p_v =P(Z>2)=0.0228$

5) Conclusion

If we compare the p value and the significance level assumed, for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.

4 0

3 years ago

NOT DRAWN TO SCALE. find x

WARRIOR [948]

Picture? I cant answer when there us no picture?

7 0

3 years ago

What is the answer to this?

NARA [144]

Answer:

See work for 3 answers

Step-by-step explanation:

You can add the exponents

$(-8)^{12}$

also could be stated as

$(8)^{12}$

numerical value

6.87194767 × $10^{10}$

5 0

4 years ago

Please help!!!!

tatyana61 [14]

Answer:

Step-by-step explanation:

From the figure attached,

If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.

Therefore, sides sides CD and GH must be equal in measures.

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of the side CD having ends C(-4, 4) and D(0, 5) will be,

CD = $\sqrt{(-4-0)^2+(4-5)^2}$

CD = $\sqrt{(16+1)}$

= $\sqrt{17}$

Length of GH having ends G(0, -4) and H(4, -5) will be,

GH = $\sqrt{(0-4)^2+(-4+5)^2}$

= $\sqrt{16+1}$

= $\sqrt{17}$

Therefore, m(CD) = m(GH)

Similarly, we can prove all corresponding sides of two figures equal in measure.

This shows ABCD ≅ EFGH.

3 0

3 years ago