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IceJOKER [234]
4 years ago
14

To determine the concentration of chloride ion (Cl-) in a 100 mL sample of ground water, a chemist adds a large enough volume of

AgNO3 solution to precipitate all Cl- as AgCl. The mass of the resulting precipitate is 93.9 mg. What is the chloride ion concentration in milligrams of chloride per liter of ground water
Chemistry
1 answer:
Orlov [11]4 years ago
5 0

Answer:

[Cl^-]=232.3\frac{mgCl^-}{L}

Explanation:

Hello,

In this case, we can represent the chemical reaction as:

Cl^-(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NO_3^-(aq)

In such a way, since the mass of the obtained silver chloride is 93.9 mg, we can compute the chloride ions in the ground water by using the following stoichiometric procedure whereas the molar mass of chloride ions and silver chloride are 35.45 g/mol and 143.32 g/mol respectively:

m_{Cl^-}=93.3mgAgCl*\frac{1mmolAgCl}{143.32mgAgCl}*\frac{1mmolCl^-}{1mmolAgCl} *\frac{35.45mgCl^-}{1mmolCl^-} =23.23mgCl^-

Finally, for the given volume of water in liters (0.100L), we compute the required concentration:

[Cl^-]=\frac{23.2mgCl^-}{0.100L}\\

[Cl^-]=232.3\frac{mgCl^-}{L}

Best regards.

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NeX [460]

Answer: 0.15 g/mL

Explanation:

Density = mass/vol

3 0
3 years ago
It usually takes Vaughn 12 minutes to drive to school. She drives an average of 50.0 miles per hour. What is the distance from s
lilavasa [31]
<h3>Answer:</h3>

  = 633,600 Inches

<h3>Explanation:</h3>

Speed refers to the rate of change in distance traveled by a body in motion.

It is the ratio of distance to time taken.

It is calculated by;

Speed = Distance ÷time taken

Therefore;

Distance = Speed × time

In this case;

Time taken = 12 minutes ( but 1 hr = 60 mins)

Thus, t = 0.2 hours

Speed = 50.0 miles/hour

Thus;

Distance = 50.0 miles/hr × 0.2 hours

               = 10 miles

But, we are require to give the distance in inches;

1 mile = 63360 Inches

Therefore;

10 miles = 10 × 63360 Inches

            = 633,600 Inches

6 0
3 years ago
Which of the following is TRUE?
stiks02 [169]

Answer:

Explanation:

For a general equilibrium

aA +bB ⇔ cC + dD ,

the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.

Our reasoning here should be based on the fact that  Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).

So with this in mind, lets answer this question.

1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.

2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.

3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.

4. True: From our previous reasongs this is the true one.

5. False: If K is small, the equilibrium lies on the reactants side.

8 0
3 years ago
The number of grams of H2 in 1470 mL of H2 gas. ​
Lorico [155]

Answer:

0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>

5 0
3 years ago
A gas occupies 5.6 liters at 0.860 atm. what is the pressure if the volume becomes 3.0L?
Vilka [71]
The answer is 1.6 atm. I just took the quiz.
7 0
3 years ago
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